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The orbital speed of an ice cube in the rings of Saturn is 11.2 Km/s. The correct answer is option C
<h3>What does Orbital speed depend on ?</h3>The speed of an object travelling around a circle depends on two quantities namely;
- Its angular velocity w
- Its distance from the center of the circle.
Given that an ice cube in the rings of Saturn. The mass of Saturn is 5.68 x 10^26 kg, and use an orbital radius of 3.00 x 105 km. (G= 6.67 × 10-11 N·m2/kg2)
The given parameters are:
- The mass of Saturn = 5.68 x 10^26 kg
- The orbital radius = 3.00 x 105 km
- G = 6.67 × 10-11 N·m2/kg2
Let us first calculate the gravitational field strength on the Saturn.
g = GM/r²
Substitute all the necessary parameters and convert km to m
g = (6.67 × × 5.68 ×
) ÷ (300000 × 1000)²
g = 3.79 × ÷ 9 ×
g = 0.421 m/s²
The orbital speed will be
V² = gr
V² = 0.4211 × 300000 × 1000
V² = 126333333.3
V = √126333333.3
V = 11239.8 m/s
Convert it to Km/s by dividing the answer by 1000
V = 11239.8/1000
V = 11.2 Km/s
Therefore, the orbital speed of an ice cube in the rings of Saturn is 11.2 Km/s
Learn more about Orbital Speed here: brainly.com/question/22247460
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