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Lemur [1.5K]
2 years ago
10

a central concept in quantum mechanics is that both matter and are alternate forms of the same entity and therefore both exhibit

dual characteristics of particles and of . this model allows a better understanding of the behavior of tiny particles such as electrons.
Physics
2 answers:
Stels [109]2 years ago
4 0

In quantum mechanics, a central concept is that both matter and <u>energy</u> are alternate forms of the same entity and therefore both exhibit dual characteristics of particles and of <u>waves</u>.

Matter can be defined as anything that has mass and is able to occupy space.

Thus, any physical object or substance that is found on Earth is typically composed of matter.

Similarly, energy is highly affected by the mass of a any physical object or substance just like matter,

Hence, both energy and matter are known to be made up of atoms and as a result of this fact, exhibit dual characteristics of particles and of waves.

A wave can be defined as a disturbance in a medium that progressively transports energy from a source location to another location without the transportation of matter.

In conclusion, this central concept makes it easier for us to better understand the behavior of tiny particles such as electrons.

Find more information: brainly.com/question/17203857

kkurt [141]2 years ago
4 0

Answer:

energy, waves

Explanation:

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Suppose a rocket ship accelerates upwards with acceleration equal in magnitude to twice the magnitude of g (we say that the rock
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Answer:

a) s_a=98100\ m is the height where the rocket stops accelerating and its fuel is finished and starts decelerating while it still continues to move in the upward direction.

b) v_a=1962\ m.s^{-1} is speed of the rocket going when it stops accelerating.

c) H=294300\ m

d) t_T=544.95\ s

e) Zero, since the average velocity is the net displacement per unit time and when the rocket strikes back the earth surface the net displacement is zero.

Explanation:

Given:

acceleration of rocket, a=2g=2\times 9.81=19.62\ m.s^{-2}

time for which the rocket accelerates, t_a=100\ s

<u>For the course of upward acceleration:</u>

using eq. of motion,

s_a=ut+\frac{1}{2}at_a^2

where:

u= initial velocity of the rocket at the launch =0

s_a= height the rocket travels just before its fuel finishes off

so,

s_a=0+\frac{1}{2}\times 19.62\times 100^2

a) s_a=98100\ m is the height where the rocket stops accelerating and its fuel is finished and starts decelerating while it still continues to move in the upward direction.

<u>Now the velocity of the rocket just after the fuel is finished:</u>

v_a=u+at_a

v_a=0+19.62\times 100

b) v_a=1962\ m.s^{-1} is speed of the rocket going when it stops accelerating.

After the fuel is finished the rocket starts to decelerates. So, we find the height of the rocket before it begins to fall back towards the earth.

Now the additional height the rocket ascends before it begins to fall back on the earth after the fuel is consumed completely, at this point its instantaneous velocity is zero:

using equation of motion,

v^2=v_a^2-2gh

where:

g= acceleration due to gravity

v= final velocity of the rocket at the top height

0^2=1962^2-2\times 9.81\times h

h=196200\ m

c) So the total height at which the rocket gets:

H=h+s

H=196200+98100

H=294300\ m

d)

Time taken by the rocket to reach the top height after the fuel is over:

v=v_a+g.t

0=1962-9.81t

t=200\ s

Now the time taken to fall from the total height:

H=v.t'+\frac{1}{2}\times gt'^2

294300=0+0.5\times 9.81\times t'^2

t'=244.95\ s

Hence the total time taken by the rocket to strike back on the earth:

t_T=t_a+t+t'

t_T=100+200+244.95

t_T=544.95\ s

e)

Zero, since the average velocity is the net displacement per unit time and when the rocket strikes back the earth surface the net displacement is zero.

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Answer:

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Answer:

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Explanation:

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In meteorology it is used to describe the level of saturated soil above the water table

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