a central concept in quantum mechanics is that both matter and are alternate forms of the same entity and therefore both exhibit
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1) The gravitational force between Ellen and the moon is
2) The two forces are equal, while the acceleration of the bus is smaller than the acceleration of the bicycle.
Explanation:
1)
The magnitude of the gravitational force between two objects is given by
where
is the gravitational constant
are the masses of the two objects
r is the separation between them
In this problem, we have:
is the mass of Ellen
is the mass of the moon
is the distance between Ellen and the moon
Substituting, we find the gravitational force between Ellen and the moon:
2)
We can analyze the forces acting in the collision between the bus and the bicycle by using Newton's third law of motion, which states that:
"When an object A exerts a force (called action) on an object B, then object B exerts an equal and opposite force (called reaction) on object A"
Applied to our problem, this means that the force exerted by the bus on the bicycle during the collision (action force) is equal (and opposite) to the force exerted by the bicycle on the bus (reaction force).
Now let's analyze the accelerations of the two vehicles. We can find the acceleration of each vehicle by using Newton's second law:
where
a is the acceleration
F is the force exerted on the vehicle
m is the mass of the vehicle
As we said previously, the force F exerted on each of the two vehicles: so, the acceleration only depends on the mass. In particular, the acceleration is inversely proportional to the mass: therefore, the larger the mass of the vehicle, the smaller the acceleration. This means that the acceleration of the bus is smaller than the acceleration of the bicycle.
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Answer:
Explanation:
Given that
Mass of rifle = M
Initial velocity ,u= 0
Mass of bullet = m
velocity of bullet = v
Lets take final speed of the rifle is V
There is no any external force ,that is why linear momentum of the system will be conserve.
Initial linear momentum = Final linear momentum
M x 0 + m x 0 = M x V + m v
0 = M x V + m v
Negative sign indicates that ,the recoil velocity will be opposite to the direction of bullet velocity.
If the earth's mass were half its actual value but its radius stayed the same, the escape velocity of the earth would be .
The ratio of the object's travel distance over a specific period of time is known as its velocity. As a vector quantity, the velocity requires both the magnitude and the direction. the slowest possible speed at which a body can break out of the gravitational pull of a certain planet or another object.
The formula to calculate the escape velocity of earth is given below:-
Given that earth's mass was half its actual value but its radius stayed the same. The escape velocity will be calculated as below:-
.
Therefore, If the earth's mass were half its actual value but its radius stayed the same, the escape velocity of the earth would be .
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