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Mars2501 [29]
3 years ago
8

I was wondering how to set this problem up and solve it, the answer I kept getting was 41 and want a second opinion on the answe

r.

Mathematics
1 answer:
MissTica3 years ago
4 0
G (x) = 2(-2)-2 f(x)=(2)^2+5
=-4-2 =4+5
=-6 =9

-6×9= -54
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Solve the following system of equations algebraic<br> y=x^2+3x-29<br> y=2x-9
Lady bird [3.3K]

Step-by-step explanation:

Given equations:

       y  = x² + 3x - 29    ------ (i)

       y  = 2x - 9  ---------------- (ii)

Now to solve this problem, we must determine the value of x and y;

 Equate equations 1 and 2;

       x² + 3x - 29 = 2x - 9

       x² + 3x - 2x - 29 + 9  = 0

       x² + x - 20  = 0

       x² + 5x - 4x - 20  = 0

       x(x + 5 ) - 4(x + 5) = 0

      (x - 4) (x+ 5) = 0

       x  - 4  = 0 or x + 5  = 0

      x  = 4 or x = -5;

So;   solve for y now;

     y = 2x - 9

     input x  = 4 or x = -5;

    y  = 2(4) - 9 or y = 2(-5) - 9

    y = -1 or y = -19

7 0
3 years ago
The distance between the two points (4,1) and (9,1) is​
Rzqust [24]

Answer:

5 units. Since they have the same y coordinate the x coordinate determines the distance from each other. In the case 9-4=5.

6 0
3 years ago
50 PTS ANSWER ALL &lt;3333333
11Alexandr11 [23.1K]

QUESTION 33

The length of the legs of the right triangle are given as,

6 centimeters and 8 centimeters.

The length of the hypotenuse can be found using the Pythagoras Theorem.

{h}^{2}  =  {6}^{2}  +  {8}^{2}

{h}^{2}  = 36+ 64

{h}^{2}  = 100

h =  \sqrt{100}

h = 10cm

Answer: C

QUESTION 34

The triangle has a hypotenuse of length, 55 inches and a leg of 33 inches.

The length of the other leg can be found using the Pythagoras Theorem,

{l}^{2}  +  {33}^{2}  =  {55}^{2}

{l}^{2}  =  {55}^{2}  -  {33}^{2}

{l}^{2}  = 1936

l =  \sqrt{1936}

l = 44cm

Answer:B

QUESTION 35.

We want to find the distance between,

(2,-1) and (-1,3).

Recall the distance formula,

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the values to get,

d=\sqrt{( - 1-2)^2+(3- - 1)^2}

d=\sqrt{( - 3)^2+(4)^2}

d=\sqrt{9+16}

d=\sqrt{25}

d = 5

Answer: 5 units.

QUESTION 36

We want to find the distance between,

(2,2) and (-3,-3).

We use the distance formula again,

d=\sqrt{( - 3-2)^2+( - 3- 2)^2}

d=\sqrt{( - 5)^2+( - 5)^2}

d=\sqrt{25+25}

d=\sqrt{50}

d=5\sqrt{2}

Answer: D

8 0
3 years ago
Read 2 more answers
HELPPPPPP make sure your right !:)
makvit [3.9K]
To find your constant of variation, you just need to figure out what you multiply the x by in order to get f(x). In other words, what do you multiply the 3 by to get 6? What do you multiply the 7 by to get 14? Another way to think of it is to divide f(x) by the x to get your constant. 
4 0
3 years ago
Please help me on 1-107
Ksenya-84 [330]
A is 25
B is 45
C is 30
3 0
3 years ago
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