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Sphinxa [80]
3 years ago
14

The spring-mounted 0.84-kg collar A oscillates along the horizontal rod, which is rotating at the constant angular rate rad/s. A

t a certain instant, r is increasing at the rate of 610 mm/s.
If the coefficient of kinetic friction between the collar and the rod is 0.61, calculate the friction force F exerted by the rod on the collar at this instant.
Physics
1 answer:
vfiekz [6]3 years ago
8 0

Answer:

Friction = 5.027 N

Explanation:

Kinetic friction does not change with speed or acceleration. The only thing that is required is to state that the object is moving.

Solving the force equation for friction we get:

Friction = coefficient of friction* normal force exerted by the object

Friction = u * R

here R is = 0.84 * Gravity = 0.84 * 9.81 = 8.2404 N

u = 0.61 (as stated in the question)

So frictional force will be:

Friction = 0.61 * 8.2404

Friction = 5.027 N

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A rock is dropped off a cliff and falls the first half of the distance to the ground in 2.0 seconds. how long will it take to fa
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Answer:

The answer is 0.83 seconds.

Explanation:

The formula of free fall is following:

h=1/2*g*t^2

Where g=9.8 m/s^2 and t=2 seconds, the rock takes:

h=1/2*9.8*2^2=19.6

19.6 meters. This is the half distance of the cliff. The whole distance is 39.2 meters. So it takes:

39.2=1/2*9.8*t^2\\t^2=8\\t=2.83

2.83 second to fall down completely. The rock takes the second half of the cliff in 0.83 seconds

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3 years ago
Suppose a certain car supplies a constant deceleration of A meter per second per second. If it is traveling at 90km/hr. When. th
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Answer:

i)-6.25m/s

ii)18 metres

iii)26.5 m/s or 95.4 km/hr

Explanation:

Firstly convert 90km/hr to m/s

90 × 1000/3600 = 25m/s

(i) Apply v^2 = u^2 + 2As...where v(0m/s) is the final speed and u(25m/s) is initial speed and also s is the distance moved through(50 metres)

0 = (25)^2 + 2A(50)

0 = 625 + 100A....then moved the other value to one

-625 = 100A

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(ii) Firstly convert 54km/hr to m/s

In which this is 54 × 1000/3600 = 15m/s

then apply the same formula as that in (i)

0 = (15)^2 + 2(-6.25)s

-225 = -12.5s

Hence the stopping distance = 18metres

(iii) Apply the same formula and always remember that the deceleration values is the same throughout this question

0 = u^2 + 2(-6.25)(56)

u^2 = 700

Hence the speed that the car was travelling at is the,square root of 700 = 26.5m/s

In km/hr....26.5 × 3600/1000 = 95.4 km/hr

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3 years ago
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To change a substance from one state to another, extreme temperatures or pressures are required. Sometimes when a substance doesn't change states we should use all the ideas when that happens. To create a solid, we should decrease the temperature by a huge amount and then add pressure. For example, oxygen will solidify at -361.8 degrees Fahrenheit at standard pressure. However, it will freeze at warmer temperatures when the pressure is increased.

Phase changes happen when a substance reach some special points. Sometimes when a liquid becomes a solid a freezing point or melting point is used to measure the temperature at which a liquid changes into a solid. Some of the phase changes are: Condensation, Freezing, Melting.

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