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Verizon [17]
3 years ago
9

Which lists the order of Energy Career Pathways from the source to the customer?

Engineering
2 answers:
iragen [17]3 years ago
8 0

Answer:

(A)  Energy Generation, Energy Transmission, Energy Distribution

Luden [163]3 years ago
4 0

Answer:

answer is A. EG,Et, and Ed

Explanation:

You might be interested in
A thin rim with a mean diameter of 1.2 m cross-section of 15 mm x 200 mm is subjected to an internal pressure of 10 MPa and rota
Soloha48 [4]

Answer:

The net centrifugal force over the rim is 30000N, the radial stress is 397887 Pa and the total change in diameter is 4.98 mm.

Explanation:

Lets first calculate the force in the rim due to the centrifugal force. For doing this we may assume that the centrifugal force is constant along with thick because of the thin thick.

Fc = m.ω^2/R

Where m is the mass, w the angular speed and R the mean radius.  The mass is computing by the rim density and its volume:

m=p.V

m=p*(A*R)

Where A is the cross-sectional area in meters:

m=((0.015m*0.200m)*0.6m)*(7800 kg/m^3)=28.08 kg

The angular speed in rad/s is:

ω = 800r/m . 1m/60s = 133.33 r/s

Thus the centrifugal force is:

Fc = (28.08 kg)*(133.33 rad/s)^2*(0.6m) = 299505N = 30000N

Note that the calculating value is the net contribution to the whole rim but the centrifugal force is distributed along the rim's external area:

fc = Fc / (2π .R .b)

Where b is rim's with equal to 200mm :

fc = 300000 N / (2π*0.6m*0.2m) = 397887 N/m^2

The centrifugal force can be taken as internal pressure:

Pfc = 397887 N/m^2 = 3978787 Pa

As both pressures act expanding the rim it can be summed:

Pt=Pi+Pfc

Pt = 10MPa+397887Pa= 10000000Pa+397887Pa= 10397887Pa

Then for a thinner thick the stress is calculated by:

Pt*d =2σr*t

Take into account that the stress σr is over the radial direction. Then solving for o and by replacing the total pressure:

σr = Pt.d/(2*t)

σr = 10397887 Pa / (2*0.015m*0.2m) = 415915480Pa = 415MPa

We know that the radial specific deformation ε is:

σr = E / εr

εr = σr / E

For a young modulus of 200GPa:

εr = 415MPa / 200GPa

εr = 415MPa / 200000MPa=0.002075

By definition the specific deformation is written in terms of the total change in the radius:

εr = Δr / R

Δr = R / εr =0.002075 * 1.2 m = 0.00249m

As we need the change in diameter:

Δd = 2Δr =0.00498m= 4.98mm [/tex]

5 0
3 years ago
Tengo un problema con steam y es que sale como que no he comprado un juego pero en realidad si lo he comprado pero por una pagin
kvv77 [185]

Answer:

Cómo forzar a Steam a reconocer los juegos instalados.

1) Vuelva a instalar los juegos sin descargar.

2) Agregue la carpeta Steam Library manualmente.

3) Reconocer juegos de una nueva unidad

4) Utilizar .acf Cache para forzar el reconocimiento de juegos de Steam .acf Cache para forzar el reconocimiento de juegos de Steam.

Explanation:

1) Vuelva a instalar los juegos sin descargar.

- Inicia Steam y ve a Juegos.

- Seleccione y haga clic en instalar para el juego que Steam no pudo reconocer.

- Steam comenzará a descubrir los archivos existentes para el juego.

2) Agregue la carpeta Steam Library manualmente.

- Lanzar Steam.

- Haga clic en Steam y seleccione Configuración.

- Haz clic en la pestaña Descargas.

- Haga clic en las carpetas de la biblioteca de Steam.

- En la ventana emergente, haz clic en Agregar carpeta de biblioteca y selecciona la ubicación donde se guardan todos los datos de tu juego Steam.

- Haga clic en Seleccionar y cerrar la configuración de Steam.

- Salga de la aplicación Steam y reinicie Steam.

- Steam ahora debería reconocer los juegos instalados nuevamente y enumerarlos en la carpeta de juegos.

3) Reconocer juegos de una nueva unidad

- Inicie la aplicación Steam desde el escritorio.

- Haz clic en Steam y selecciona Configuración.

- Haz clic en la pestaña Descargas.

- Haga clic en la carpeta de la biblioteca de Steam en la sección Bibliotecas de contenido.

- Haga clic en Agregar carpeta de biblioteca y navegue a la ubicación donde se mueven sus juegos (nuevo directorio) que es D: / games / your_subdirectory.

- Haga clic en Seleccionar y cerrar para guardar la carpeta de la biblioteca.

- Salga de Steam y reinícielo.

Steam escaneará la carpeta Biblioteca recientemente seleccionada y mostrará todos los juegos instalados.

4) Utilizar .acf Cache para forzar el reconocimiento de juegos de Steam .acf Cache para forzar el reconocimiento de juegos de Steam.

- Asegúrese de haber reinstalado Steam o tener la instalación existente.

- Mueva los datos del juego a C: >> Archivos de programa (x86) >> Steam >> carpeta Steamapps.

- Lanzar Steam.

- En este punto, Steam puede mostrar algunos juegos que están instalados correctamente.

- Para los juegos que se muestran como no instalados, seleccione y haga clic en el botón Instalar.

- Steam comenzará a descubrir todos los archivos existentes.

- Sin embargo, si Steam no reconoce los archivos existentes, comenzará a descargar los archivos y el progreso leerá 0%.

- Pausa la actualización de los juegos y sal de Steam. Vaya a C: >> Archivos de programa (x86) >> Steam >> Steamapps y encuentre todos los archivos .acf actuales.

¡¡¡Espero que esto ayude!!!

3 0
4 years ago
Select the correct answer.
bonufazy [111]

Answer:

OD.

plate

Explanation:

3 0
3 years ago
An inductor is connected to a voltage source and it is found that it has a time constant, t. When a 10-ohm resistor is placed in
prisoha [69]

Answer:

A) 30 mH

B ) 10-ohm

Explanation:

resistor = 10-ohm

Inductor = 30mH ( l )

L = inductance

R = resistance

r = internal resistance

values of the original Inductors

Note : inductor = constant time (t)  case 1

inductor + 10-ohm resistor connected in series = constant time ( t/2) case2

inductor + 10-ohm resistor + 30 mH inductance in series = constant time (t) case3

<em>From the above cases</em>

case 1 = time constant ( t ) = L / R

case 2 = Req = R + r hence time constant  t / 2  = L / R + r  therefore

t = \frac{2L}{R+r}

case 3 = Leq = L + l , Req = R + r .  constant time ( t )

hence Z = \frac{L + l}{R + r} = t

A) Inductance

To calculate inductance equate case 1 to case 3

\frac{L}{R} = \frac{L + l}{R + r} =   L / 10 = (L + 30) / ( 10 + 10 )

= 20 L = 10 L + 300 mH

   10L = 300 m H

therefore L = 30 mH

B ) The internal resistance

equate case 1 to case 2

\frac{L}{R} = \frac{2L}{R + r}

R + r = 2 R  therefore  ( r = R )   therefore internal resistance = 10-ohm

6 0
3 years ago
Q5) Write C++ program to find the summation of sines of the even values that can be divided by 7 between -170 and -137.
Minchanka [31]

Answer:

In C++:

#include <iostream>

#include <cmath>

using namespace std;

int main(){

 double total = 0;

 for(int i = -170; i<=-130;i++){

     if(i%2 == 0 && i%7==0){

         double angle = i*3.14159/180;

         total+=sin(angle);      }  }

 cout<<"Total: "<<total;

 return 0; }

Explanation:

This initializes the total to 0

 double total = 0;

This iterates from -170 to - 130

 for(int i = -170; i<=-130;i++){

This checks if the current number is even and is divided by 7

     if(i%2 == 0 && i%7==0){

This converts the number from degrees to radians

         double angle = i*3.14159/180;

This adds the sine of the number

         total+=sin(angle);      }  }

This prints the calculated total

 cout<<"Total: "<<total;

5 0
3 years ago
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