What are two reasons why Hunter edjucation is important? 30 pts
1 answer:
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Answer:
1.
2. 163.3 m
Explanation:
Static friction between road and rubber, μs =0.06
The maximum speed of the car, v = 50 km/h
= (50)(1000/3600) m/s
= 13.89 m/s
The acceleration due to gravity,
The frictional force, f = μsN ...... (1)
The component mg cosθ which balance the normal reaction N
The component mg sinθ acts in an opposite direction to the frictional force f.
ΣF = mg sinθ-f = 0 ...... (2)
Substitute the equation (1) in equation (2), we get
ΣF = mgsinθ-μsN = 0
mgsinθ-μsmgcosθ =0
μs = sinθ/cosθ
tanθ = μs
θ = tan-1( μs) = tan-1(0.06) =
(b)The vertical component of the force is
N cosθ = fsinθ+mg
N cosθ = μsNsinθ+mg
N[cosθ- μs sinθ] = mg ...... (3)
The horizontal component of the force along the motion of the car is
Nsinθ+fcosθ = ma (Centripetal acceleration,
Nsinθ+fcosθ =
Nsinθ+μsNcosθ =
N[sinθ+μs cosθ] = ...... (4)
Dividing the equation (4) with equation (3),
[sinθ+μscosθ]/[cosθ- μs sinθ] =
cosθ[sinθ/cosθ+μs]/cosθ[1- μs sinθ/cosθ] =
[tanθ+μs]/[1-μs tanθ] =
From part (1), tanθ = μs
Then the above equation becomes
Therefore, the minimum radius of the curvature of the curve is
=
=
= 163.3 m
Answer:
The correct answer is option (A) 0.060 uF
Note: Kindly find an attached image of the complete question below
Sources: The complete question was well researched from Quizlet.
Explanation:
Solution
Given that:
C₁ = 0.1 μF
C₂ =0.22 μF
C₃ = 0.47 μF
In this case, C₁, C₂ and C₃ are in series
Thus,
Their equivalent becomes:
1/Ceq = (1/C₁ + 1/C₂ +1/C₃
1/Ceq =[ (1/0.1 + 1/0.22 +1/0.47)]
1/Ceq =[(0.22 * 0.47) + (0.1 * 0.47) + (0.1 * 0.22)/(0.1 * 0.22 *0.47)]
1/Ceq =[(0.1034 + 0.047 + 0.022)/(0.01034)
1/Ceq =[(0.1724)/(0.01034)]
1/Ceq = [(16.67)]
1/Ceq =(1/16.67) = 0.059μf
Ceq = 0.059μf ≈ 0.060μf
Therefore the equivalent capacitance of the three series capacitors is 0.060μf
