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Verizon [17]
3 years ago
13

A car is pulled with a force of 10,000 N. The car's mass is 1267 kg. But, the car covers 394.6 m in 15 seconds

Physics
1 answer:
Rasek [7]3 years ago
6 0

F=m*a=>a=F/m=10000/1267=7.89 m/s²

d=v₀t+a't²/2<=>394.6=112.5*a'=>a'=3.5

a-a'=7.89-3.5=4.39 m/s²

This difference causes friction forces

We apply the second principle of dynamics: vector: F + N + G + Ff = ma (vector vectors, I can not here)

Scalar: Ox: F-Ff = ma

            Oy N-mg = 0

Ff = -ma+ F =-1267*7.89+10000=-8869+10000=1131 N

This frictional force (Ff) is opposite to the traction (F)


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Each lunar cycle has one full moon, in which the relative positions of Earth, the sun, and the moon form in a straight line
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Complete Question:

Each lunar cycle has one full moon, in which the relative positions of Earth, the sun, and the moon form in a straight line. Which list represents the position of Earth, the sun, and the moon during a full moon?

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D. sun, Earth, moon

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3 0
3 years ago
Scientists use tables and graphs to chart and analyze _________.
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Consider two celestial objects with masses m1 and m2 with a separation distance between their centers r. If the first mass m1 we
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The new magnitude of the force of attraction will be 6 times the original force of attraction

<h3>How to determine the initial force </h3>
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  • Mass 2 = m₂
  • Gravitational constant = G
  • Distance apart = r
  • Initial force (F₁) = ?

F = Gm₁m₂ / r²

F₁ = Gm₁m₂ / r²

<h3>How to determine the new force </h3>
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  • Mass 2 = 3m₂
  • Gravitational constant = G
  • Distance apart (r) = r
  • New force (F₂) =?

F = Gm₁m₂ / r²

F₂ = G × 2m₁ × 3m₂ / r²

F₂ = 6Gm₁m₂ / r²

But

F₁ = Gm₁m₂ / r²

Therefore

F₂ = 6Gm₁m₂ / r²

F₂ = 6F₁

Thus, the new magnitude of the force of attraction will be 6 times the original force of attraction

Learn more about gravitational force:

brainly.com/question/21500344

#SPJ1

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