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lora16 [44]
1 year ago
9

Scientists observe that iron compounds are able to bind to nutrients in waterways experiencing eutrophication. Which change will

most likely occur if iron compounds are added to a lake with an overabundance of nutrients? (1 point)
1. Fewer microorganisms will grow on the surface of the lake
2. More areas of hypoxia will occur in the lake.
3. More contaminated water will reach the lake.
4. Less sunlight will reach aquatic plants in the lake.

Which phrase best describes fracking?(1 point)

1. removing the top layer of an ore-bearing mountain to access oil and gas resources
2. using water and chemicals at high pressure to open up fissures to access oil and gas resources
3. using water and chemicals at high pressure to open up fissures to access mineral resources
4. removing the top layer of an ore-bearing mountain to access mineral resources

SOMEONE PLEASE HELP QUICK!!!
Chemistry
1 answer:
Anettt [7]1 year ago
6 0

(1) Fewer microorganisms will grow on the surface of the lake if iron compounds are added to a lake with an overabundance of nutrients. Hence, option 1 is correct.

(2) Fracking means using water and chemicals at high pressure to open up fissures to access oil and gas resources. Hence, option 2 is correct.

<h3>What are microorganisms?</h3>

An organism that can be seen only through a microscope.

Iron is a natural capping agent which can enhance sediment P binding capacity, thus reducing P availability and shifting a lake from an algal to a macrophyte dominated state. Iron could, however, also impose toxic effects on the biota.

Fracking is the injection of a fluid at high pressure into an underground rock formation to open fissures and allow trapped gas or crude oil to flow through a pipe to a wellhead at the surface.

This technique is used in natural gas and petroleum production.

1) Fewer microorganisms will grow on the surface of the lake if iron compounds are added to a lake with an overabundance of nutrients. Hence, option 1 is correct.

(2) Fracking means using water and chemicals at high pressure to open up fissures to access oil and gas resources. Hence, option 2 is correct

Learn more about the microorganisms here:

brainly.com/question/6699104

#SPJ1

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The heats of combustion of ethane (C2H6) and butane (C4H10) are 52 kJ/g and 49 kJ/g, respectively. We need to produce 1.000 x 10
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Answer :

(1) The number of grams needed of each fuel (C_2H_6)\text{ and }(C_4H_{10}) are 19.23 g and 20.41 g respectively.

(2) The number of moles of each fuel (C_2H_6)\text{ and }(C_4H_{10}) are 0.641 moles and 0.352 moles respectively.

(3) The balanced chemical equation for the combustion of the fuels.

C_2H_6+\frac{7}{2}O_2\rightarrow 2CO_2+3H_2O

C_4H_{10}+\frac{13}{2}O_2\rightarrow 4CO_2+5H_2O

(4) The number of moles of CO_2 produced by burning each fuel is 1.28 mole and 1.41 mole respectively.

The fuel that emitting least amount of CO_2 is C_2H_6

Explanation :

<u>Part 1 :</u>

First we have to calculate the number of grams needed of each fuel (C_2H_6)\text{ and }(C_4H_{10}).

As, 52 kJ energy required amount of C_2H_6 = 1 g

So, 1000 kJ energy required amount of C_2H_6 = \frac{1000}{52}=19.23g

and,

As, 49 kJ energy required amount of C_4H_{10} = 1 g

So, 1000 kJ energy required amount of C_4H_{10} = \frac{1000}{49}=20.41g

<u>Part 2 :</u>

Now we have to calculate the number of moles of each fuel (C_2H_6)\text{ and }(C_4H_{10}).

Molar mass of C_2H_6 = 30 g/mole

Molar mass of C_4H_{10} = 58 g/mole

\text{ Moles of }C_2H_6=\frac{\text{ Mass of }C_2H_6}{\text{ Molar mass of }C_2H_6}=\frac{19.23g}{30g/mole}=0.641moles

and,

\text{ Moles of }C_4H_{10}=\frac{\text{ Mass of }C_4H_{10}}{\text{ Molar mass of }C_4H_{10}}=\frac{20.41g}{58g/mole}=0.352moles

<u>Part 3 :</u>

Now we have to write down the balanced chemical equation for the combustion of the fuels.

The balanced chemical reaction for combustion of C_2H_6 is:

C_2H_6+\frac{7}{2}O_2\rightarrow 2CO_2+3H_2O

and,

The balanced chemical reaction for combustion of C_4H_{10} is:

C_4H_{10}+\frac{13}{2}O_2\rightarrow 4CO_2+5H_2O

<u>Part 4 :</u>

Now we have to calculate the number of moles of CO_2 produced by burning each fuel to produce 1000 kJ.

C_2H_6+\frac{7}{2}O_2\rightarrow 2CO_2+3H_2O

From this we conclude that,

As, 1 mole of C_2H_6 react to produce 2 moles of CO_2

As, 0.641 mole of C_2H_6 react to produce 0.641\times 2=1.28 moles of CO_2

and,

C_4H_{10}+\frac{13}{2}O_2\rightarrow 4CO_2+5H_2O

From this we conclude that,

As, 1 mole of C_4H_{10} react to produce 4 moles of CO_2

As, 0.352 mole of C_4H_{10} react to produce 0.352\times 4=1.41 moles of CO_2

So, the fuel that emitting least amount of CO_2 is C_2H_6

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