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lora16 [44]
1 year ago
9

Scientists observe that iron compounds are able to bind to nutrients in waterways experiencing eutrophication. Which change will

most likely occur if iron compounds are added to a lake with an overabundance of nutrients? (1 point)
1. Fewer microorganisms will grow on the surface of the lake
2. More areas of hypoxia will occur in the lake.
3. More contaminated water will reach the lake.
4. Less sunlight will reach aquatic plants in the lake.

Which phrase best describes fracking?(1 point)

1. removing the top layer of an ore-bearing mountain to access oil and gas resources
2. using water and chemicals at high pressure to open up fissures to access oil and gas resources
3. using water and chemicals at high pressure to open up fissures to access mineral resources
4. removing the top layer of an ore-bearing mountain to access mineral resources

SOMEONE PLEASE HELP QUICK!!!
Chemistry
1 answer:
Anettt [7]1 year ago
6 0

(1) Fewer microorganisms will grow on the surface of the lake if iron compounds are added to a lake with an overabundance of nutrients. Hence, option 1 is correct.

(2) Fracking means using water and chemicals at high pressure to open up fissures to access oil and gas resources. Hence, option 2 is correct.

<h3>What are microorganisms?</h3>

An organism that can be seen only through a microscope.

Iron is a natural capping agent which can enhance sediment P binding capacity, thus reducing P availability and shifting a lake from an algal to a macrophyte dominated state. Iron could, however, also impose toxic effects on the biota.

Fracking is the injection of a fluid at high pressure into an underground rock formation to open fissures and allow trapped gas or crude oil to flow through a pipe to a wellhead at the surface.

This technique is used in natural gas and petroleum production.

1) Fewer microorganisms will grow on the surface of the lake if iron compounds are added to a lake with an overabundance of nutrients. Hence, option 1 is correct.

(2) Fracking means using water and chemicals at high pressure to open up fissures to access oil and gas resources. Hence, option 2 is correct

Learn more about the microorganisms here:

brainly.com/question/6699104

#SPJ1

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Ideal gas molecules do not attract or repel each other. The only interaction between ideal gas molecules would be an elastic collision upon impact with each other or an elastic collision with the walls of the container. [What is an elastic collision?]

Ideal gas molecules themselves take up no volume. The gas takes up volume since the molecules expand into a large region of space, but the Ideal gas molecules are approximated as point particles that have no volume in and of themselves.

If this sounds too ideal to be true, you're right. There are no gases that are exactly ideal, but there are plenty of gases that are close enough that the concept of an ideal gas is an extremely useful approximation for many situations. In fact, for temperatures near room temperature and pressures near atmospheric pressure, many of the gases we care about are very nearly ideal.

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7 0
3 years ago
Read 2 more answers
When of alanine are dissolved in of a certain mystery liquid , the freezing point of the solution is less than the freezing poin
LenaWriter [7]

The question is incomplete, the complete question is:

When 177. g of alanine (C_3H_7NO_2) are dissolved in 800.0 g of a certain mystery liquid X, the freezing point of the solution is 5.9^oC lower than the freezing point of pure X. On the other hand, when 177.0 g of potassium bromide are dissolved in the same mass of X, the freezing point of the solution is 7.2^oC lower than the freezing point of pure X. Calculate the van't Hoff factor for potassium bromide in X.

<u>Answer:</u> The van't Hoff factor for potassium bromide in X is 1.63

<u>Explanation:</u>

Depression in the freezing point is defined as the difference between the freezing point of the pure solvent and the freezing point of the solution.

The expression for the calculation of depression in freezing point is:

\Delta T_f=i\times K_f\times m

OR

\Delta T_f=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times w_{solvent}\text{(in g)}} ......(1)

  • <u>When alanine is dissolved in mystery liquid X:</u>

\Delta T_f=5.9^oC

i = Vant Hoff factor = 1 (for non-electrolytes)

K_f = freezing point depression constant

m_{solute} = Given mass of solute (alanine) = 177. g

M_{solute} = Molar mass of solute (alanine) = 89 g/mol

w_{solvent} = Mass of solvent = 800.0 g

Putting values in equation 1, we get:

5.9=1\times K_f\times \frac{177\times 1000}{89\times 800}\\\\K_f=\frac{5.9\times 89\times 800}{1\times 177\times 1000}\\\\K_f=2.37^oC/m

  • <u>When KBr is dissolved in mystery liquid X:</u>

\Delta T_f=7.2^oC

i = Vant Hoff factor = ?

K_f = freezing point depression constant = 2.37^oC/m

m_{solute} = Given mass of solute (KBr) = 177. g

M_{solute} = Molar mass of solute (KBr) = 119 g/mol

w_{solvent} = Mass of solvent = 800.0 g

Putting values in equation 1, we get:

7.2=i\times 2.37\times \frac{177\times 1000}{119\times 800}\\\\i=\frac{7.2\times 119\times 800}{2.37\times 177\times 1000}\\\\i=1.63

Hence, the van't Hoff factor for potassium bromide in X is 1.63

7 0
3 years ago
Which of the following is not a mixture?
MakcuM [25]

Answer:

Sugar

Explanation:

Mixtures are substances that made of two or more elements or other substances that are joined together by physical methods and when mixed can be also be separated by physical method into the original individual elements.

Air is a mixture of gases such as oxygen, nitrogen, carbon dioxide and rare gases. When an amount of air is collected, its constituents can be collected separately.

Likewise 7 up and sea water

Sugar is a compound made of carbon, hydrogen and oxygen, when sugar is decomposed, it's original constituents are not recovered but sugar is decomposed into carbon dioxide and water

4 0
3 years ago
Determine the volume in mL of 0.37 M HClO4(aq) needed to reach the half-equivalence (stoichiometric) point in the titration of 2
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Answer:

14.3mL you require to reach the half-equivalence point

Explanation:

A strong acid as HClO₄ reacts with a weak base as CH₃CH₂NH₂, thus:

CH₃CH₂NH₂ + HClO₄ → CH₃CH₂NH₃⁺ + ClO₄⁻

As the reaction is 1:1, to reach the equivalence point you require to add the moles of HClO₄ equal to moles CH₃CH₂NH₂ you add originally. Also, half-equivalence point requires to add half-moles of CH₃CH₂NH₂ you add originally.

Initial moles of CH₃CH₂NH₂ are:

20.8mL = 0.0208L × (0.51mol CH₃CH₂NH₂ / 1L) =

0.0106moles CH₃CH₂NH₂

To reach the half-equivalence point you require:

0.0106moles ÷ 2 = 0.005304 moles HClO₄

As concentration of HClO₄ is 0.37M, volume you require to add 0.005304moles is:

0.005304 moles HClO₄ ₓ (1L / 0.37mol) = 0.0143L =

<h3> 14.3mL you require to reach the half-equivalence point</h3>

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3 years ago
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