Answer:
86.4 m horizontal from landing spot
Explanation:
Find out how long before the ball hits the ground
vertical speed of ball = -2 m/s gravity = - 9.81 m/s^2
find time to hit ground from 100 m
( height will be<u> zero</u> when it hits the ground)
<u>0 </u>= 100 - 2 t - 1/2 ( 9.81) t^2
use Quadratic Formula to find t = 4.32 seconds
horizontal speed of ball = 20 m/s
in 4.32 seconds it will travel horizontally 20 m/s * 4.32 s = 86.4 m
If we neglect friction/air resistance, then the horizontal component
doesn't change, and the vertical component becomes (9.8 m/s downward)
greater each second thanks to gravity.
So, after 2 seconds, the horizontal component is still 40 m/s, and the
vertical component is (30 - 2·9.8) = 10.4 m/s upward.
Choice #1 says this.
Answer:
Explanation:
stiffness k = 160
m = 10
angular frequency ω = 
= 
= 4
ω = 4
Let x = 4 - A sinωt
when t = 0
x = 4 in
when t = 2 s , x = - 4
- 4 = 4 - A sinωt
8 = A sin 4 x 2
8 = A sin8
A = 8 / sin 8
= 8 / .989
= 8.09 in .
x = 4 - A sinωt
dx / dt = - Aω cosωt
v = - Aω cosωt
for t = 0
v = - Aω
= - 8.09 x 4
= - 32.36 in / s
initial velocity v = - 32.36 in /s
displacement x for t = 4s
x = 4 - 8.09 sin 4 x 4
= 4 - 8.09 sin 16
= 4 - 8.09 x - .2879
= 4 + 2.33
= 6.33 in.
c ) Amplitude of vibration A = 8.09 in .as calculated above .
The height of the bullet when the velocity is zero is 256 ft.
<h3>Height of the bullet when the velocity is zero </h3>
The height of the bullet when the velocity is zero is determined by taking derivative of the function as shown below;
The height of the bullet at this time is calculated as follows;
Learn more about height of projectiles here: brainly.com/question/10008919
Answer: perpendicular to it oscillations.
Explanation: A transverse wave is a wave whose oscillations is perpendicular to the direction of the wave.
By perpendicular, we mean that the wave is oscillating on the vertical axis (y) of a Cartesian plane and the vibration is along the horizontal axis (x) of the plane.
Examples of transverse waves includes wave in a string, water wave and light.
Let us take a wave in a string for example, you tie one end of a string to a fixed point and the other end is free with you holding it.
If you move the rope vertically ( that's up and down) you will notice a kind of wave traveling away from you ( horizontally) to the fixed point.
Since the oscillations is perpendicular to the direction of wave, it is a transverse wave
