The length of the spring 2 due to arrangement of the equal masses is determined as 0.238 m.
<h3>Extension of the spring 2</h3>
The extension of the spring 2 is determined from the net force acting on spring 2.
F(net) = Kx
<em>Net force on spring 2 = sum of forces acting downwards - sum of forces acting upwards.</em>
Net force on spring 2 = (force on 2 + force on 3) - (force on 1)
F(net) = (m₂ + m₃)g - (m₁)g
F(net) = (6.67 + 6.67)9.8 - (6.67)9.8
F(net) = 130.732 - 65.366
F(net) = 65.366 N
x = F/k
x = (65.366)/(8130)
x = 0.00804 m
The length of spring 2 = x + 0.23 m
= 0.00804 m + 0.23 m = 0.238 m
Thus, the length of the spring 2 due to arrangement of the equal masses is determined as 0.238 m.
Learn more about extension of elastic material here: brainly.com/question/26838571
Answer:
I know one answer is an observer on earth sees a lunar eclipse
We Know, P = m*v
Here, m = 30 Kg
v = 5 m/s
Substitute it into the expression,
P = 30*5 Kgm/s
P = 150 Kgm/s
So, your final answer is 150 Kg.m/s
Hope this helps!
The resultant displacement between the two vectors will increase.
The resultant of the two vectors is given by parallelogram law of vectors.
The parallelogram law of vector addition states that if two vectors are represented in magnitude and direction by the adjacent sides of a parallelogram, the diagonal of the parallelogram drawn from the point of intersection of the vectors represents the resultant vector in magnitude and direction.
The resultant of these vectors, say vector A, and B, is given as;
When;
θ = 90°
When;
θ = 120°
Thus, the resultant displacement between the two vectors will increase.
Learn more here: brainly.com/question/20885836
