What is reflection of light

1 answer:

4 0

Answer: When a ray of light approaches a smooth polished surface and the light ray bounces back, it is called the reflection of light. The incident light ray which lands upon the surface is said to be reflected off the surface. The ray that bounces back is called the reflected ray.

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Which of the following are heterogeneous mixtures (not homogeneous mixtures)?

BARSIC [14]

The following are heterogeneous mixture: MILK THAT IS SOLD AT THE STORE, A CAKE MIX AND MIXED NUT.An heterogeneous mixture is one which contained many parts which can be separated out.A smoothie is an homogeneous mixture because the juice of different fruits that are use can not be separated out.
Read more on Brainly.com - brainly.com/question/4731209#readmore

5 0

2 years ago

A particle is projected with velocity v0 directly up a slope which makes an angle α with the horizontal. Assume frictionless mot

Nikolay [14]

Answer:

a)T total = 2*Voy/(g*sin( α ))

b)α = 0º , T total≅∞ (the particle, goes away horizontally indefinitely)

α = 90º, T total=2*Voy/g

Explanation:

Velocity in the Y axis:

Voy=Vo*sinα

Time to reach the maximal height :

Kinematics equation: Vfy=Voy-at

a=g*sinα ; g is gravity

if Vfy=0 ⇒ t=T ; time to reach the maximal height

so:

0=Voy-g*sin( α )*T

T=Voy/(g*sin( α ))

Time required to return to the starting point:

After the object reaches its maximum height, the object descends to the starting point, the time it descends is the same as the time it rises.

So T total= 2T = 2*Voy/(g*sin( α ))

α = 0º , sinα=0

The particle goes totally horizontal, goes away indefinitely

T total= 2*Voy/(g*sin( α )) ≅∞

α = 90º, sinα=1

T total=2*Voy/g

6 0

3 years ago

Compare wave A with wave B correctly in relation to amplitude.

olga nikolaevna [1]

We know for a fact that D and A can be eliminated from the answer choices because those are both false. we know that both B and C are both very accurate knowing that wave B does have a higher pitch than wave A but also wave A has a louder sound wave than wave B. so i'd say the answer is (C).

8 0

2 years ago

Two identical conducting spheres, A and B, carry equal charge. They are stationary and are separated by a distance much larger t

podryga [215]

Answer:

8F_i = 3F_f

Explanation:

When two identical spheres are touched to each other, they equally share the total charge. Therefore, When neutral C is first touch to A, they share the initial charge of A equally.

Let us denote that the initial charge of A and B are Q. Then after C is touched to A, their respective charges are Q/2.

Then, C is touched to B, and they share the total charge of Q + Q/2 = 3Q/2. Their respective charges afterwards is 3Q/4 each.

The electrostatic force, Fi, in the initial configuration can be calculated as follows.

$F_i = \frac{1}{4\pi\epsilon_0}\frac{q_Aq_B}{r^2} = \frac{1}{4\pi\epsilon_0}\frac{Q^2}{r^2}[/tex}The electrostatic force, Ff, in the final configuration is [tex]F_f = \frac{1}{4\pi\epsilon_0}\frac{q_Aq_B}{r^2} = \frac{1}{4\pi\epsilon_0}\frac{3Q^2/8}{r^2}[/tex}Therefore, the relation between Fi and Ff is as follows[tex]F_i = F_f\frac{3}{8}\\8F_i = 3F_f$