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4 years ago

6

a ball slows down as it rolls up hill this is an example of? neutral motion, relative velocity, positive acceleratio, negative a

cceleration

2 answers:

Zarrin [17]4 years ago

8 0

Answer: negative acceleration

Explanation:

Acceleration is speeding up, the ball is slowing down making it negative acceleration

tensa zangetsu [6.8K]4 years ago

6 0

Answer:

4th option

Explanation:

You might be interested in

just want to double-check that you understand a practical consequence of the expansion of the universe. Light reaches us from a

Daniel [21]

Answer:

<em>The distance of the light is 9.4608 x 10^25 m</em>

<em></em>

Explanation:

Time taken by the light = 10 billion years = 10 x 10^9 years

speed of light = 3 x 10^8 m/s

speed of light in m/years is = (3 x 10^8)/(60 x 60 x 24 x 365) = 9.4608 x 10^15 m/year

distance = speed x time

therefore, the distance of this light = 10 x 10^9 x 9.461 x 10^15 = <em>9.4608 x 10^25 m</em>

4 0

4 years ago

A baseball is thrown at an angle of 25 degrees relative to the ground at a speed of 23 m/s. If the ball was caught 42 m from the

ExtremeBDS [4]

Answer:

a) $v_{0y} = 9.72 m/s$

b) $v_{0x} = 20.85 m/s$

c) $t = 2.01 s$

d) $h_{max} = 4.82 m$

Explanation:

a) The initial vertical velocity is given by:

$v_{0y} = v*sin(\theta)$

Where:

θ: 25°

v: is the magnitude of the speed = 23 m/s

$v_{0y} = 23 m/s*sin(25) = 9.72 m/s$

b) The initial horizontal velocity can be calculated as follows:

$v_{0x} = v*cos(\theta) = 23 m/s*cos(25) = 20.85 m/s$

c) The flight time can be calculated using the following equation:

$v_{0x} = \frac{x}{t}$

Where:

x: is the total distance = 42 m

$t = \frac{x}{v_{0x}} = \frac{42 m}{20.85 m/s} = 2.01 s$

d) The maximum height is given by:

$v_{fy}^{2} = v_{0y}^{2} - 2gh_{max}$

Where:

$v_{fy}$ : is the final vertical velocity =0 (at the maximum heigth)

g: is the gravity = 9.81 m/s²

$h_{max} = \frac{v_{0y}^{2}}{2g} = \frac{(9.72 m/s)^{2}}{2*9.81 m/s^{2}} = 4.82 m$

I hope it helps you!

7 0

3 years ago

Two blocks a and b ($m_a>m_b$) are pushed for a certain distance along a frictionless surface. how does the magnitude of the

Yuki888 [10]

Answer:

the magnitude of the work done by the two blocks is the same.

Explanation:

The work done by block a on block b is given by:

$W_a = F_a d$

where Fa is the force exerted by block a on block b, and d is the distance they cover.

The work done by block b on block a is given by:

$W_b = F_b d$

where Fb is the force exerted by block b on block a, and d is still the distance they cover.

For Newton's third law, the force exerted by block a on block b is equal to the force exerted by block b on block a, therefore

$F_a = F_b$

and so

$W_a=W_b$

3 0

3 years ago

A particle passes through the point P=(−3,1,0)P=(−3,1,0) at time t=3t=3, moving with constant velocity v⃗ =⟨5,3,−2⟩v→=⟨5,3,−2⟩.

eimsori [14]

Answer:

The parametric equation for the position of the particle is $(-18+5t,-8+3t,6-2t)$ .

Explanation:

Given that,

The point is

$P=(-3,1,0)$

Time t = 3

Velocity $v=(5,3,-2)$

We need to calculate the parametric equation for the position of the particle

Using parametric equation for position

$r(t)=r_{0}+v(t)t$ ....(I)

at t = 3,

$P=r(t)$

Put the value into the formula

$(-3,1,0)=r_{0}+(5,3,-2)\times3$

$(-3,1,0)=r_{0}+(15,9,-6)$

$r_{0}=(-18,-8,6)$

Put the value of r₀ in equation (I)

$r(t)=(-18,-8,6)+(5,3,-2)t$

$r(t)=(-18+5t,-8+3t,6-2t)$

Hence, The parametric equation for the position of the particle is $(-18+5t,-8+3t,6-2t)$ .

3 0

3 years ago

List one advantage and one disadvantage of a manual water hose.

RoseWind [281]

Are you referring to a manual water garden hose? If so then a advantage is that you can water in certain areas you would like that sprinklers may not reach, one disadvantage is that you have to spend time watering by hand.

8 0

3 years ago