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BartSMP [9]
2 years ago
10

Which object would best be identified by a periodic Doppler shift in a star's spectrum along with a dip in the stars light inten

sity?
a black hole
a nebula
a comment
a planet
Chemistry
1 answer:
IgorLugansk [536]2 years ago
5 0
The answer would be a planet<span>. Planets revolve around stars, which means there will come a point where the planet is between the star and our field of vision towards the star. This point will be where the star's radiation will have the lowest intensity. As the planet moves, the intensity will change. The effect is comparable to a lunar or solar eclipse.</span>
You might be interested in
What is the number of electrons shared in the multiple carbon-carbon bond in one molecule of 1-pentyne?
jeka57 [31]
Where the options are?
8 0
3 years ago
How many atoms are in .47 moles of argon
lesantik [10]

Answer:

\large \boxed {2.8 \times 10^{23}\text{ atoms Ar}}

Explanation:

\text{Atoms of Ar} = \text{0.47 mol Ar} \times \dfrac{ 6.022  \times 10^{23}\text{ atoms Ar}}{\text{1 mol Ar}}\\\\= \large \boxed {\mathbf{2.8 \times 10^{23}}\textbf{ atoms Ar}}

3 0
2 years ago
100 PIONTSSSSS HELP ASAP
valina [46]

Left Panel

Short answer A

<em><u>Solution</u></em>

Since you have been given choices, my sloppy numbers will do, but it anyone is going to see this, YOU SHOULD CLEAN  THEM UP WITH THE NUMBERS THAT COME FROM YOUR PERIODIC TABLE.

Equation

Sodium Phosphate + Calcium Chloride ===> Sodium Chloride + Calcium Phosphate.

Na3PO4 + CaCl2 ===> NaCl + Ca3(PO4)2

<em><u>Step One</u></em>

Balance the Equation

2Na2PO4 + 3CaCl2 ==> 6NaCl + Ca3(PO4)2

<em><u>Step Two</u></em>

Find the molar mass of CaCl2

Ca = 40

2Cl = 71

Molar Mass = 40 + 71 = 111 grams/mole

<em><u>Step Three</u></em>

Find the number of moles of CaCl2

Given mass = 379.4

Molar Mass = 111

moles = given Mass / molar Mass

moles of CaCl2 = 379.4/111 = 3.418 moles

<em><u>Step Four</u></em>

Find the number of moles of Ca3(PO4)2 needed.

This requires that you use the balance numbers from the balanced equation.

For every 3 moles of CaCl2 you have, you get 1 mole of Ca3(PO4)2

n_moles of Ca3(PO4)2 = 3.418 / 3 = 1.13933 moles

<em><u>Step Five</u></em>

Find the molar mass of Ca3(PO4)2

From the periodic table,

3Ca = 3 * 40 = 120

2 P  = 2 * 31 =    62

8 O = 8 * 16   =128

Molar Mass = 120 + 62 + 128= 310 grams per mole.

<em><u>Step Six</u></em>

1 mole of Ca3(PO4)2 has a molar mass of 310 gram

1.13933 moles of Ca3(PO4)2 = x

x = 1.13933 moles * 310 grams /mole

x = 353.2 grams. As you can see, even with my rounding I'm only out 0.3 of a gram. DON'T FORGET TO PUT THIS TO THE PROPER SIG DIGS IF SOMEONE ELSE IS GOING TO SEE IT.

Middle Panel

Short Answer C

Equation

2HCl + Mg ===> H2 + MgCl2

The object of the first part of the game is to find the number of moles of H2.

<em><u>Step One</u></em>

Find the moles of HCl

1 mole HCl = 35.5 + 1 = 36.5

n = given mass divided by molar mass

n = 49 grams / 36.5 = 1.34 moles.

The balanced equation tells you that for ever mole of H2 produced, you need 2 moles of HCl. That's what the balance numbers are for.

So the number of moles of H2 is 1.34 / 2 = 0.671 moles of H2.

Now we come to Part II. We have to use an new friend of yours that I have seen only once before from you.

Find V using PV = nRT

R is going to be in kPa so the value of R = 8.314

V = ???

n = 0.671 moles

T = 25 + 273 = 298oK

P = 101.3 kPa

101.3 * V= 0.671*8.314 * 298

V = 0.671 * 8.314 * 298 / 101.3

V = 16.4

The answer is C and again, I have rounded almost everything except R, although it can go out to 8 places.

Right Panel

I can't see the panel. I don't know what the problem is. Never mind I got it. I'm going to be a little skimpy on this one since I've done two like it and they are long.

LiOH + HBr ===> LiBr + H2O and the equation is balanced.

You have to figure out the moles of LiOH and HBr. Use the LOWEST number of moles

n_LiOH = given mass / molar mass = 117/(7 + 16 + 1) = 117 / 24 = 4.875 moles

n_HBr = given mass / molar mass =  141/(1 + 80) = 141 / 81 = 1.741 moles

HBr is the lower number. That's all the LiBr you are going to get is 1.741. There is no adjustment to be made from the balance equation.

n = given mass / molar mass  multiply both sides by the molar mass

n * Molar mass (LiBr) = n * (7 + 80) = 1.741 * 87 = 151 grams of

The answer is C


6 0
2 years ago
The specific heat of copper is 0.40 joules/ g °c. How much heat is needed in joules to change the temperature of a 55 gram subst
Snezhnost [94]

Answer : The amount of heat needed is, 1188 J

Explanation :

Formula used :

q=m\times c\times (T_2-T_1)

where,

q = heat needed = ?

m = mass of copper = 55 g

c = specific heat capacity of copper = 0.40J/g^oC

T_1 = initial temperature = 20.0^oC

T_2 = final temperature = 74.0^oC

Now put all the given values in the above formula, we get:

q=55g\times 0.40J/g^oC\times (74.0-20.0)^oC

q=1188J

Thus, the amount of heat needed is, 1188 J

3 0
3 years ago
I need help identifying the type of reactions. Can anyone help?
Eddi Din [679]

Answer:

Reaction 5: Decomposition reaction.

Reaction 6: Single replacement reaction

Reaction 7: Combination reaction.

Reaction 8: Combustion reaction.

Explanation:

<u><em>Reaction 5:</em></u>    2KClO₃ → 2KCl + 3O₂.

  • It is a decomposition reaction.
  • A decomposition reaction is a type of chemical reaction in which a single compound breaks down into two or more elements or new compounds.
  • In this reaction: potassium chlorate decomposes into two single components (potassium chloride and oxygen).
  • So, it is a decomposition reaction.

<u><em>Reaction 6:</em></u> Zn + 2HCl → H₂ + ZnCl₂.

  • It is a single replacement reaction.
  • A single-replacement reaction, a single-displacement reaction, is a reaction by which one (or more) element(s) replaces an/other element(s) in a compound.
  • It is most often occur if element is more reactive than the other, thus giving a more stable product.
  • In this reaction, zinc metal (more active) displaces the hydrogen to form hydrogen gas and zinc chloride, a salt. Zinc reacts quickly with the acid to form bubbles of hydrogen.

<u><em>Reaction 7:</em></u> N₂O₅ + H₂O → 2HNO₃.

  • It is a combination "synthesis" reaction.
  • A synthesis reaction has two or more reactants and only one product.
  • In this reaction, dinitrogen pentoxide reacts with water to produce nitric acid.
  • So, it is considered as a synthetic "combination" reaction.

<u><em>Reaction 8:</em></u> 2C₂H₆ + 7O₂ →  4CO₂ + 6H₂O.

  • It is a combustion reaction.
  • A combustion reaction is a reaction where hydrocarbon alkane is completely burned in oxygen to produce water and carbon dioxide.
  • In this reaction 1.0 mole of ethane is burned to give 4.0 moles of carbon dioxide and 6.0 moles of water.
  • So, it is considered as a combustion reaction.
7 0
3 years ago
Read 2 more answers
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