Answer:
<h2>464.85 mL</h2>
Explanation:
The new volume can be found by using the formula for Boyle's law which is
![P_1V_1 = P_2V_2](https://tex.z-dn.net/?f=P_1V_1%20%3D%20P_2V_2)
Since we're finding the new volume
![V_2 = \frac{P_1V_1}{P_2} \\](https://tex.z-dn.net/?f=V_2%20%3D%20%20%5Cfrac%7BP_1V_1%7D%7BP_2%7D%20%20%5C%5C)
100.7 kPa = 100,700 Pa
95.1 kPa = 95,100 Pa
We have
![V_2 = \frac{100700 \times 439}{95100} = \frac{44207300}{95100} \\ = 464.8506...](https://tex.z-dn.net/?f=V_2%20%3D%20%20%5Cfrac%7B100700%20%5Ctimes%20439%7D%7B95100%7D%20%20%3D%20%20%5Cfrac%7B44207300%7D%7B95100%7D%20%20%5C%5C%20%20%3D%20464.8506...)
We have the final answer as
<h3>464.85 mL</h3>
Hope this helps you
Answer:
11 electrons total and 23amu
Explanation:
This tells us that sodium has 11 protons and because it is neutral it has 11 electrons. The mass number of an element tells us the number of protons AND neutrons in an atom (the two particles that have a measurable mass). Sodium has a mass number of 23amu.
Answer:
49.2 g/mol
Explanation:
Let's first take account of what we have and convert them into the correct units.
Volume= 236 mL x (
) = .236 L
Pressure= 740 mm Hg x (
)= 0.97 atm
Temperature= 22C + 273= 295 K
mass= 0.443 g
Molar mass is in grams per mole, or MM=
or MM=
. They're all the same.
We have mass (0.443 g) we just need moles. We can find moles with the ideal gas constant PV=nRT. We want to solve for n, so we'll rearrange it to be
n=
, where R (constant)= 0.082 L atm mol-1 K-1
Let's plug in what we know.
n=![\frac{(0.97 atm)(0.236 L)}{(0.082)(295K)}](https://tex.z-dn.net/?f=%5Cfrac%7B%280.97%20atm%29%280.236%20L%29%7D%7B%280.082%29%28295K%29%7D)
n= 0.009 mol
Let's look back at MM=
and plug in what we know.
MM= ![\frac{0.443 g}{0.009 mol}](https://tex.z-dn.net/?f=%5Cfrac%7B0.443%20g%7D%7B0.009%20mol%7D)
MM= 49.2 g/mol
Answer:
The Answer would be B (Materials can be seen in picometers which are trillionths of a meter or the size atoms.
Explanation:
Answer:
Explanation:
Hello,
We are required to write the chemical formula of the following compounds
1. Calcium nitride = Ca₃N₂
2. Magnesium Phosphide = Mg₃P₂
3. Rubidium Chromate = Rb₂CrO₄
4. Aluminium nitrate = Al(NO₃)₃
5. Ammonium Arsenide = (NH₄)₃As
6. Nickel(ii) nitrite = Ni(NO₂)₂
7. Copper(i)sulfate = Cu₂SO₄
8. Iron(iii)nitrate = Fe(NO₃)₃
9. Manganese(ii)nitrate = Mn(NO₃)₂
The left hand side are the common names when the right hand side are the chemical formula.