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ss7ja [257]
3 years ago
6

cho các chất sau NaO2,Na,NaOH,Na2SO4,Na2SO3,NaCl,AgCl hãy lập thành dãy chuyển hoá , hoàn thành bằng phương tình phản ứng

Chemistry
1 answer:
Archy [21]3 years ago
5 0

Answer:

brainless me plss i help you out

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If the concentration of the stock (provided) Cu(NH3)42 was 0.041 M, what concentration will the Cu2 be in beaker?
kodGreya [7K]

Answer:

[Cu^{2+}]=0.041 M

Explanation:

Hello!

In this case, since the molarity of a solution is defined in terms of the moles of the solute and the volume of solution, given that the concentration of Cu(NH₃)₄²⁺ is 0.041 M, and there is only one copper atom per Cu(NH₃)₄²⁺ ion, we can compute the concentration of Cu²⁺ as shown below:

[Cu^{2+}]=0.041\frac{molCu(NH_3)_4^{2+}}{L}*\frac{1molCu^{2+}}{1molCu(NH_3)_4^{2+}} =0.041 \frac{molCu(NH_3)_4^{2+}}{L}

[Cu^{2+}]=0.041 M

Best regards!

6 0
3 years ago
What are the physical properties of liquid bleach
Archy [21]
I think it is Sodium,hypochlorite
6 0
3 years ago
A gas container has a volume of 446.9 with a temp of 14c. When the volume is decreased to 238.7l the new temp is what
swat32

Answer:

\frac{V _{1}}{T _{1}}  =  \frac{V _{2}}{T _{2} }  \\  \frac{446.9}{(14 + 273)}  =  \frac{238.7}{T _{2} } \\ {T _{2}} =  \frac{238.7 \times 287}{446.9}  \\ {T _{2}} = 153.3 \: kelvin \\  = 119.7  \degree \: c

7 0
3 years ago
The reaction described in Part A required 3.40 L of sodium chloride. What is the concentration of this sodium chloride solution
Mumz [18]

Answer:

Part A:

First, convert molarity to moles by multiplying by the volume:

0.293 M AgNO3 = (0.293 moles AgNO3)/1 L x 1.19 L = 0.349 moles AgNO3

5 0
3 years ago
Describe the term molarity as it relates to an acid or base.
Sidana [21]
Molarity is expressed as the number of moles of solute per volume of the solution. For example, we are given a solution of 2M NaOH this describes a solution that has 2 moles of NaOH per 1 L volume of the solution. Acids and bases can be measured through the concentrations of H+ and OH- ions in units of molarity. Hope this helps.
4 0
4 years ago
Read 2 more answers
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