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monitta
3 years ago
10

DAY 5: 10/28-29/21

Mathematics
1 answer:
kaheart [24]3 years ago
5 0

Answer:

A

Step-by-step explanation:

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Can someone please give me the answer to the second part of this question?<br> Thank You!
Elena-2011 [213]

Answer:

\theta=30\textdegree

Step-by-step explanation:

(ii)\ \sqrt{3}\tan\ \theta=2\sin \theta\\\\substitute\ \tan\theta=\frac{\sin\theta}{\cos\theta}\\\\\sqrt{3}\frac{\sin\theta}{\cos\theta}=2\sin\theta\\\\Divide\ both\ sides\ by\ \sin\theta.\\\\\sqrt{3}\frac{\sin\theta}{\cos\theta\times \sin\theta}=\frac{2\sin\theta}{\sin\theta}\\\\\frac{\sqrt{3}}{\cos\theta}=\frac{2}{1}\\\\Apply\ cross\ multiplication\\\\2\cos\theta=\sqrt{3}\\\\divide\ both\ sides\ by\ 2\\\\\frac{2\cos\theta}{2}=\frac{\sqrt{3}}{2}\\\\\cos\theta=\frac{\sqrt{3}}{2}\\\\

\cos\theta=\cos\ 30\textdegree\\\\\theta=30\textdegree

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-3x+2y=11\qquad\text{add 3x to both sides}\\\\2y=3x+11\qquad\text{divide both sides by 2}\\\\y=\dfrac{3}{2}x+\dfrac{11}{2}\\\\for\ x=1\to y=\dfrac{3}{2}(1)+\dfrac{11}{2}=\dfrac{3}{2}+\dfrac{11}{2}=\dfrac{14}{2}=7\to(1,\ 7)\\\\for\ x=-3\to y=\dfrac{3}{2}(-3)+\dfrac{11}{2}=-\dfrac{9}{2}+\dfrac{11}{2}=\dfrac{2}{2}=1\to(-3,\ 1)\\\\for\ x=-5\to y=\dfrac{3}{2}(-5)+\dfrac{11}{2}=-\dfrac{15}{2}+\dfrac{11}{2}=-\dfrac{4}{2}=-2\to(-5,\ -2)

3 0
4 years ago
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