<u>Acceleration</u> is the rate at which <u>velocity</u> changes.
Answer:
ΔU = 5.21 × 10^(10) J
Explanation:
We are given;
Mass of object; m = 1040 kg
To solve this, we will use the formula for potential energy which is;
U = -GMm/r
But we are told we want to move the object from the Earth's surface to an altitude four times the Earth's radius.
Thus;
ΔU = -GMm((1/r_f) - (1/r_i))
Where;
M is mass of earth = 5.98 × 10^(24) kg
r_f is final radius
r_i is initial radius
G is gravitational constant = 6.67 × 10^(-11) N.m²/kg²
Since, it's moving to altitude four times the Earth's radius, it means that;
r_i = R_e
r_f = R_e + 4R_e = 5R_e
Where R_e is radius of earth = 6371 × 10³ m
Thus;
ΔU = -6.67 × 10^(-11) × 5.98 × 10^(24)
× 1040((1/(5 × 6371 × 10³)) - (1/(6371 × 10³))
ΔU = 5.21 × 10^(10) J
Answer: 249 seconds
Explanation:
Speed of bike = 2.52 m/s
Distance = 628 m
Time taken = ? ( let the unknown value be Z)
Recall that speed is the distance covered per unit time.
Hence, speed = Distance / Time taken
Time taken = Distance / speed
Z = 628m / 2.52 m/s
Z = 249.2 seconds (Round to nearest tenth i.e 249 seconds)
Thus, it takes 249 seconds for the girl to get to her friends house
Answer:
14.49 g/cm²
Explanation:
I = Io e^-(ux)
Where:
I = 573
Io = 1045
x = 0.3 inches and
rho = 11.4g/cm^3
Using the conversion constant
1 inch = 2.54 cm;
0.3 inches = 0.3 * 2.54 cm
0.3 inches = 0.762 cm
I/Io = e^-(ux), or say
Io/I = e^(ux), taking the In of both sides
ln(Io/I) = ux, making u subject of formula
u = 1/x * ln(Io/I)
u = 1/0.762 * ln(1045/573)
u = 1.312 * 0.6
u = 0.787
Next, we say that
u/rho = 0.7872/11.4 = 0.069
And finally, we make
1/(u/rho) to be our final answer
Inverse of the answer is = 14.49 g/cm²
Therefore, the um^-1 in g/cm^2? is 14.49
