Answer:
impulse = force x time
impulse = 1900000 x 0.005 = 9500Ns
Answer:
a. 2.668 m/s
b. 0.00494
Explanation:
The computation is shown below:
a. As we know that


As the wind does not move the skater to the east little work is performed in this direction. All the work goes in the direction of the N-S. And located in that direction the component of the Force.
F = 3.70 cos 45 = 2.62 N


We know that
KE1 = Initial kinetic energy
KE2 = kinetic energy following 100 m
The energy following 100 meters equivalent to the initial kinetic energy less the energy lost to the work performed by the wind on the skater.
So, the equation is
KE2 = KE1 - W

Now solve for v2


= 2.668 m/s
b. Now the minimum value of Ug is
As we know that
Ff = force of friction
Us = coefficient of static friction
N = Normal force = weight of skater
So,

Now solve for Us


= 0.00494
Answer: Is there supposed to be something elses here because this question is unclear.
Explanation:
Answer:

Explanation:
Assuming the crate does not lift above the ground and remains along the floor, then its acceleration will be in the horizontal direction. Therefore, we can use Newton's second law to find its acceleration:

where
is the net force on the crate along the x-direction
m is the mass of the crate
is the acceleration
Here we have:
m = 50.0 kg
is the component of the pulling force along the horizontal direction
Solving for the acceleration,

<span>the acceleration of an object is depedent upon two variables
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