Answer:
External locus of control
Explanation:
External locus of control is an attitude people possess that makes them attribute their failures or successes to factors other than themselves. The opposite of this type of attitude is the Internal locus of control where the individuals take responsibility for the outcomes of their actions whether good or bad. One good thing about the external locus of control is that when the individuals with this characteristic record successes, they attribute it to others and this presents them as people with team spirit. However, when they record failures, they do not want to take the blame, but rather attribute it to others.
Fred exhibits an external locus of control because he attributed his speeding to other factors like the road signs and GPS instead of fully admitting that it was his fault.
Answer:
The terrestrial planets in order from smallest to largest are :
Explanation:
Answer:
The answer is 'an equinox'.
<u>Answer</u>:
<em>Dog drinking water after it feels thirsty is an example of an organism responding to its internal environment to maintain homeostasis.
</em>
<u>Explanation</u>:
The regulation of temperature of the body of an organism is called homeostasis. <em>Warm blooded organisms depend on their internal environment to maintain homeostasis while cold blooded organisms</em> completely depend on their external environment to maintain homeostasis.
The <em>body temperatures of warm blooded organisms maintain its constancy despite changing temperature of the external environment</em>. But the case of cold blooded organisms is different.
Their body temperature completely depends on the external environment and thus they have<em> several behavioral and physiological adaptations to maintain their body temperatures </em>at the comfortable level.
<em>In this example dog is a warm blooded animal and it drinks water to maintain homeostasis since water helps in thermal regulation of its body.
</em>
Answer:
v = (78.0 i ^ - 70.27 j ^) m/s, v = 105 m / s
, θ = 318º
Explanation:
We have a projectile launch problem, let's start by calculating the time it takes to get through the canyon
y = t - ½ gt2
As the motorcyclist comes out horizontally, the speed he has is the horizontal speed (vox) and the initial vertical speed is zero (I go = 0)
y = 0 - ½ g t2
t = √ 2y / g
t = √ (2 252 /9.8)
t = 7.17 s
Let's calculate the vertical speed for this time
= - gt
= 0 - gt
= - 9.8 7.17
= - 70.27 m / s
We can give the result in two ways
First:
v = (78.0 i ^ - 70.27 j ^) m / s
Second:
using the Pythagorean theorem and trigonometry
v² = vₓ² + ²
v = √ [(78.0)² + (-70.42)²] = √ (11042.98)
v = 105 m / s
tan θ₁ = y / vₓ
tan θ₁ = -70.42 / 78.0
θ₁ = 42º
If we measure this angle from the positive direction of the x-axis counterclockwise
θ = 360 - θ₁
θ = 360 - 42
θ = 318º