Ask question

Ask question

All categories

2 years ago

9

este tipo de desarrollo se refiere al desarrollo de la mente es la capacidad de pensar razonar y usar el lenguaje informal ideas

que es?

1 answer:

algol132 years ago

6 0

Answer:

yed

Explanation:

You might be interested in

The wave that carrys the most energy are the waves that?

lesya [120]

"<em>The different types of radiation are defined by the the amount of </em><em>energy</em><em> found in the photons. Radio </em><em>waves</em><em> have photons with low energies, microwave photons have a little </em><em>more energy</em><em> than radio </em><em>waves</em><em>, infrared photons have still </em><em>more</em><em>, then visible, ultraviolet, X-rays, and, the </em><em>most</em><em> energetic of all, gamma-rays.</em>"

5 0

2 years ago

Read 2 more answers

What is a good sentence using relative dating

emmasim [6.3K]

You could certainly have some good easy going carefree conversation with your sister or your cousin at dinner or at a movie, but relative dating is not an effective way to get serious and find a life partner.

8 0

2 years ago

How much mass should be attached to a vertical ideal spring having a spring constant (force constant)of 39.5 N/m so that it will

nordsb [41]

Answer:

m = 1 kg

Explanation:

Given that,

The force constant of the spring, k = 39.5 N/m

The frequency of oscillation, f = 1 Hz

The frequency of oscillation is given by the formula as formula as follows :

$f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}} \\\\f^2=\dfrac{k}{4m\pi^2}\\\\m=\dfrac{k}{4\pi^2 f^2}\\\\m=\dfrac{39.5}{4\pi^2 \times (1)^2}\\\\m=1\ kg$

So, the mass that is attached to the spring is 1 kg.

6 0

2 years ago

A 129-kg horizontal platform is a uniform disk of radius 1.51 m and can rotate about the vertical axis through its center. A 67.

blondinia [14]

Answer:

I = 274.75 kg-m²

Explanation:

given,

mass of horizontal platform = 129 Kg

radius of the disk = 1.51 m

mass of the person(m_p) = 67.5 Kg

standing at distance(r_p) = 1.09 m

mass of dog(m_d) = 25.3 Kg

sitting near the person(r_d) = 1.37 m from center

moment of inertia = ?

Moment of inertia of disc = $\dfrac{1}{2}MR^2$

Moment of inertia of the system

$I = MOI\ of\ disk + m_p r_p^2 + m_d r_d^2$

$I = \dfrac{1}{2}MR^2 + m_p r_p^2 + m_d r_d^2$

$I = \dfrac{1}{2}\times 129 \times 1.51^2 + 67.5 \times 1.09^2 + 25.3\times 1.37^2$

I = 274.75 kg-m²

3 0

2 years ago

Ahh ahhh ahhh ahhh ahhh ahhh ahhh ahhh ahhh ahha aggg agg

timama [110]

shhhh hahahaha ahhhhhhhh ahhhh

4 0

2 years ago

Read 2 more answers