All categories

3 years ago

Energy captured during the ""photo"" part of photosynthesis is stored in _____ during the ""synthesis"" part of the process.

1 answer:

5 0

Energy captured during the ""photo"" part of photosynthesis is stored in <u>covalent bond</u> during the ""synthesis"" part of the process.

<u>Explanation:</u>

When carbon dioxide, water and sunlight are combindly processed by Plants, algae and a set of bacteria called cyanobacteria to become photoautotrophs, then the process goes is named as Photosynthesis. It generates oxygen, Glyceraldehyde-3-phosphate (G3P), common high-energy carbohydrate molecules which result into glucose, sucrose or other sugar molecules which comprises covalent energy-saving bonds.

Thus the species breakdown these molecules to exhibit energy for cellular functioning. In light-dependent processes, chlorophyll absorbs the radiation from the sunlight and converts it into chemical energy in the form of electron carrier derivatives such as ATP and NADPH. Carbohydrate molecules are constructed from carbon dioxide in light-independent processes i.e in the Calvin cycle, using the chemical energy obtained throughout the light-dependent processes.

You might be interested in

7. A 1000 kg car is rolling down the street at 2.5 m/s. How fast would a 2500 kg car have to

babunello [35]

1 m/s

Explanation:

To solve this question we use the following formula:

momentum = mass × velocity

momentum of the first car = 1000 kg × 2.5 m/s

momentum of the second car = 2500 kg × X m/s

To bring the cars at rest the momentum of the first car have to be equal to the momentul of the second car.

momentum of the first car = momentum of the second car

1000 kg × 25 m/s = 2500 kg × X m/s

X (velocity of the second car) = (1000 × 25) / 2500 = 1 m/s

Learn more about:

momentum

brainly.com/question/13378780

#learnwithBrainly

7 0

3 years ago

An automobile with a standard differential turns sharply to the left. The left driving wheel turns on a 20-m radius. Distance be

Inessa05 [86]

Explanation:

The given data is as follows.

Inner wheel Radius = 20 m,

Distance between left and right wheel = 1.5m,

Let us assume speed of drive shaft is N rpm.

Formula to calculate angular velocity is as follows.

Angular velocity of automobile = w = $\frac{V}{R}$

where, V = linear velocity of automobile m/min,

R = turning radius from automobile center in meter

In the given case, angular velocity remains same for inner and outer wheel but there is change in linear velocity of inner wheel and outer wheel.

Now, we assume that

u = linear velocity of inner wheel

and, u' = linear velocity of outer wheel.

Formula for angular velocity of inner wheel w = ,

Formula for angular velocity of outer wheel w =

Now, for inner wheels

w =

= $\frac{u}{(R - d)}$

u = $V \times \frac{(R - d)}{R}$

= $V \times (1 - \frac{d}{R})$

If radius of wheel is r it will cover distance in one min.

Since, velocity of wheel is u it will cover distance u in unit time(min)

Thus, u = $2\pi rn$ = $V \times (1 - \frac{d}{R})$

Now, rotation per minute of inner wheel is calculated as follows.

n = $\frac{V}{2 \pi r \times (1 - \frac{d}{R})}$

= $\frac{V}{2 \pi r \times (1 - \frac{0.75}{20})}$ (since 2d = 1.5m given, d = 0.75m),

= $\frac{V}{r} \times 0.1532$

So, rotation per minute of outer wheel; n' =

= $\frac{V}{2 \pi r \times (1 + \frac{0.75}{20})}$

= $\frac{V}{r} \times 0.1651$

5 0

3 years ago

What happens to the temperature during an endothermic reaction? ANSWERS; The temperature stays constant. The temperature will de

EleoNora [17]

Answer:

The temperature will decrease (get colder).

Explanation:

Enthalpy changes are heat changes accompanying physical and chemical changes. The enthalpy change is the difference between the sum of the heat contents of products and the sum of heat contents of reactants.

For an endothermic change, heat is absorbed for the reaction.
The surrounding becomes colder at the end of the reaction and so is the reaction itself.
The right choice is that the temperature will decrease.

6 0

3 years ago

Consider a thin, spherical shell of radius 14.5 cm with a total charge of 29.5 µC distributed uniformly on its surface. (a) Find

ra1l [238]

Answer:

10.0 zero, by Gauss' Law the symmetrical distribution will produce no internal electric fields

21.5 E = k Q / R^2 behaves as if all charge were at center

E = 9 E9 * 29.5 E-6 / .215^2 = 5.74E6 N/C

8 0

3 years ago

Q.By the method of dimensional analysis derive the

Artyom0805 [142]

Answer

a) Using dimensional analysis we cannot derive the relation, But we can check the correctness of the formula.

$s = u t +\dfrac{1}{2}at^2$

now, L H S

s = distance

dimension of distance = [M⁰L¹T⁰]

now, equation on the right hand side

R H S

u = speed

u = m/s

Dimension of speed = [M⁰L¹T⁻¹]

dimension of time

t = sec

Dimension of time = [M⁰L⁰T¹]

Dimension of 'ut' = [M⁰L¹T⁻¹][M⁰L⁰T¹]

= [M⁰L¹T⁰]

now, acceleration= a

a = m /s²

dimension of acceleration = [M⁰L¹T⁻²]

dimension of (at²) = [M⁰L¹T⁻²][M⁰L⁰T¹][M⁰L⁰T¹]

= [M⁰L¹T⁰]

hence, the dimension are balanced.

so, L H S = R H S

b) Moment of inertia of hollow sphere = $\dfrac{2}{3}Mr^2$

Moment of inertia of solid sphere = $\dfrac{2}{5}Mr^2$

we know,

$\tau = I \alpha$

$\alpha=\dfrac{\tau}{I}$

Torque is the force that causes rotation

If the same amount of torque is applied to both spheres the sphere with bigger moment of inertia would have smaller angular velocity.

Thus the solid sphere would accelerate more.

4 0

3 years ago

Read 2 more answers