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zaharov [31]
3 years ago
11

An object travels along a straight, horizontal surface with an initial speed of 2 ms. The position of the object as a function o

f time is given in the table. Which of the following graphs represents the object’s velocity as a function of time?

Physics
1 answer:
pashok25 [27]3 years ago
3 0

Answer:

The options are not provided, so i will answer in a general way.

We know that:

The movement is along a straight horizontal surface, then we have one-dimensional motion.

The speed is 2m/s

We want a graph of position vs time.

Now, remember the relation:

Distance = Speed*Time

Then we can write the position as a function of time as:

P(t) = 2m/s*t + P0

Where t is our variable, that represents time in seconds, and P0 is the position at time t = 0seconds, we can assume that this is zero.

Then the equation is:

P(t) = 2m/s*t

And the graph is something like:

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Question: What is the electric field strength at point (x,y) = ( 20 mm ,0cm)?

Answer:

The electric field at any given point of the dipole is given as:

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(0.003) is arrived at when mm is converted to m. 3.0 mm space apart was converted to a meter.

r= the point, in the question above is 20mm = 0.02m

Now, the electric field, E can be calculated by putting the values in the formula above:

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 Question: What is the electric field strength at point (x,y) = (0cm, 20 mm )?

Answer:

Here, the electric field, E= 2krp ÷ (r^2 - a^2)^2

E= 2 (9x10^9 Nm^2/c^2) (0.02m) (0.003 m) (5x10^-9c) ÷ [(0.02m)^2 - (0.003)^2]^2

= 0.0054 ÷  0.000000152881

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