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stiks02 [169]
3 years ago
5

A box contains 6 black pens, 4 blue pens, and 7 red pens. Without looking, Clarissa randomly picks a black pen out of the box. I

f she chooses another pen out of the box without replacing the first one, what is the probability that she will pick a black pen both times? Write your answer as a percent.
Group of answer choices
Mathematics
1 answer:
Irina18 [472]3 years ago
4 0

Answer:

31.35%

Step-by-step explanation:

<h3><u>Initial</u><u> </u><u>reading</u><u>:</u></h3>

In the box, there are:

  • 6 Black pens
  • 4 blue pens
  • 7 red pens

Total number of pens in the box = 6 + 4 + 7

<u>= 17</u>

<em>If we count pens as outcomes the total number of possible outcomes are 17</em>.

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3><u>New</u><u> </u><u>reading</u><u>:</u></h3>

Clarissa takes out a black pen from the box.

That reduces the number of black pens by 1 which increases the total number of pens by 1 as well.

So now:

  • Number of black pens = 6 - 1 =<u> 5 </u>
  • Total number of pens = 17 - 1 =<u> </u><u>16</u><u> </u>

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3><u>Probability</u><u>:</u></h3>

\boxed{ \mathsf{probability =  \frac{favorable \: outcomes}{total \: outcomes} }}

If we want her to pick up a black pen, and she ends up picking one. So, we can say that the outcome is in our favor.

That makes it,

  • the number of favorable outcomes = number of black pens

= 5

  • and total outcomes = Total number of pens

= 16

\implies\mathsf{probability =  \frac{5}{16} }

For showing it as some percent we'll just multiply the fraction by 100

\implies \mathsf{ \frac{5}{16} \times 100 }

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3><u>As</u><u> </u><u>a</u><u> </u><u>percent</u><u>:</u></h3>

\implies \mathsf{ \underline{ 31.25 \: \% } }

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