speed of the car at t = 10 s is given as 10 m/s
now at t = 30 s car comes to rest so v = 0
now in this velocity time graph we can say slope will show the acceleration of the car as we know that acceleration is rate of change in velocity
as we know that
now from above formula
So slope of the graph will represent the acceleration of car which is 0.5 m/s^2
Answer:
-30 °C
Explanation:
First, we have to calculate the molality (m) of the solution. If the solution is 50% C₂H₆O₂ by mass. It means that in 100 g of solution, the are 50 g of solute (C₂H₆O₂) and 50 g of solvent (water).
The molar mass of C₂H₆O₂ is 62.07 g/mol. The moles of solute are:
50 g × (1 mol / 62.07 g) = 0.81 mol
The mass of the solvent is 50 g = 0.050 kg.
The molality is:
m = 0.81 mol / 0.050 kg = 16 m
The freezing-point depression (ΔT) can be calculated using the following expression.
ΔT = Kf × m = (1.86 °C/m) × 16 m = 30 °C
where,
Kf: freezing-point constant
The normal freezing point for water is 0°C. The freezing point of the radiator fluid is:
0°C - 30°C = -30 °C
Answer:
your velocity is 2.5 m/sec
Physics- damon, Monday, December 1, 2014 at 3:27 pm force =change in momentum\ change in time or m a if m is constant
change in momentum/3=200
change in momentum =3*200 kg m/s
