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Goryan [66]
4 years ago
5

You lower a 2.50 kg textbook (remember when textbooks used to be made out of paper instead of being digital?) from a height of 1

.85 m to 1.50 m. What is its change in potential energy?
Physics
1 answer:
aev [14]4 years ago
6 0

Answer:

Change in potential energy = 8.58 J

Explanation:

Potential energy = Mass x Acceleration due to gravity x Height

Potential energy = mgh

m = 2.50 kg

g = 9.81 m/s²

Initial height, h₁ = 1.85 m

Final height, h₂ = 1.50 m

Change in potential energy = mgh₁  - mgh₂

Change in potential energy = 2.5 x 9.81 x 1.85 - 2.5 x 9.81 x 1.50

Change in potential energy = 8.58 J

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Parallax of the stars is created by
k0ka [10]
Parallax of the stars is created by :
B. Different locations of Earth in its orbit
Parallax refer to the position of an object (in this case, a star) that will look different if we view it from different positions

hope this helps
4 0
4 years ago
Read 2 more answers
A metal wire 1.50 m long has a circular cross section of radius 0.32 mm and an end-to-end resistance of 90.0 Ohms. The metal wir
elixir [45]

Answer:

So after stretching new resistance will be 0.1823 ohm

Explanation:

We have given initially length of the wire l_1=150m

Radius of the wire r_1=0.32mm=0.32\times 10^{-3}m

Resistance of the wire initially R_1=90ohm

We know that resistance is equal to R=\frac{\rho l}{A} ,here \rho is resistivity, l is length and A is area

From the relation we can say that \frac{R_1}{R_2}=\frac{l_1}{l_2}\times \frac{A_2}{A_1}

Now length of wire become 6.75 m

Volume will be constant

So A_1l_1=A_2l_2

So \pi \times (0.32)^2\times150=\pi \times r_2^2\times 6.75

r_2=1.508mm

So \frac{90}{R_2}=\frac{150}{6.75}\times \frac{1.508^2}{0.32^2}

R_2=0.1823ohm

7 0
3 years ago
A sprinter with a mass of 65 kg reaches a speed of 10 m/s during a race. Find the sprinter’s change in linear momentum.
sergiy2304 [10]

Answer:

fuuuuuuuuuuuuuuuck

Explanation:

4 0
3 years ago
A wheel with radius 0.487 m rotates 5.75 times every second. find the period of this motion.
marin [14]
Calculate the circumference of the circular path of the wheel by the equation,
    C = 2πr
where C is the circumference,
           r is the radius

Substituting the known values,
    C = 2(π)(0.487 m) = 3.06 m

Then, period of the motion will be determined by dividing the number of rotations done,
 
     T = (3.06 m) / (5.75 /s) = 0.53 s

<em>ANSWER: 0.53 s</em>
3 0
3 years ago
The time it takes a car to attain a speed of 30 m/s when accelerating from rest at 2 m/s2 is?
Blizzard [7]

Explanation:

u = 0m/s

v = 30m/s

a = 2m/s²

Using Kinematics, we have v = u + at.

Therefore t = (v - u) / a

= (30 - 0) / (2) = 15 seconds. (B)

7 0
3 years ago
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