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3 years ago

5

You lower a 2.50 kg textbook (remember when textbooks used to be made out of paper instead of being digital?) from a height of 1

.85 m to 1.50 m. What is its change in potential energy?

1 answer:

aev [14]3 years ago

6 0

Answer:

Change in potential energy = 8.58 J

Explanation:

Potential energy = Mass x Acceleration due to gravity x Height

Potential energy = mgh

m = 2.50 kg

g = 9.81 m/s²

Initial height, h₁ = 1.85 m

Final height, h₂ = 1.50 m

Change in potential energy = mgh₁ - mgh₂

Change in potential energy = 2.5 x 9.81 x 1.85 - 2.5 x 9.81 x 1.50

Change in potential energy = 8.58 J

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A beam of light strikes a sheet of glass at an angle of 56.6° with the normal in air. You observe that red light makes an angle

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Answer:

(a). Index of refraction are $n_{red}$ = 1.344 & $n_{violet}$ = 1.406

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Explanation:

We know that

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1 × $\sin 56.6$ = $n_{red}$ × $\sin 38.4$

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For violet light

1 × $\sin 56.6$ = $n_{violet}$ × $\sin 36.4$

$n_{violet}$ = 1.406

(b). Index of refraction is given by

$n = \frac{c}{v}$

$n_{red}$ = 1.344

$v_{red} = \frac{c}{n_{red} }$

$v_{red} = \frac{3(10^{8} )}{1.344}$

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This is the velocity of red light in the glass.

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$v_{violet} = \frac{3(10^{8} )}{1.406}$

$v_{violet} =$ 2.13 × $10^{8} \ \frac{m}{s}$

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3 years ago

1. The illuminance on a surface is 6 lux and the surface is 4 meters from the light source. What is the intensity of the source?

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<u>Answer</u>

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3) C. 5 meters

<u>Explanation</u>

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= 5 m

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3 years ago

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