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Goryan [66]
3 years ago
5

You lower a 2.50 kg textbook (remember when textbooks used to be made out of paper instead of being digital?) from a height of 1

.85 m to 1.50 m. What is its change in potential energy?
Physics
1 answer:
aev [14]3 years ago
6 0

Answer:

Change in potential energy = 8.58 J

Explanation:

Potential energy = Mass x Acceleration due to gravity x Height

Potential energy = mgh

m = 2.50 kg

g = 9.81 m/s²

Initial height, h₁ = 1.85 m

Final height, h₂ = 1.50 m

Change in potential energy = mgh₁  - mgh₂

Change in potential energy = 2.5 x 9.81 x 1.85 - 2.5 x 9.81 x 1.50

Change in potential energy = 8.58 J

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SVEN [57.7K]
In 2Cr2O7 there’s 2 items; Cr and O
5 0
3 years ago
Given that two vectors A = 5i-7j-3k, B = -4i+4j-8k find A×B​
WARRIOR [948]

\textbf{A}×\textbf{B}= 68\hat{\textbf{i}} + 52\hat{\textbf{j}} - 8\hat{\textbf{k}}

Explanation:

Given:

\textbf{A} = 5\hat{\textbf{i}} - 7\hat{\textbf{j}} - 3\hat{\textbf{k}}

\textbf{B} = -4\hat{\textbf{i}} + 4\hat{\textbf{j}} - 8\hat{\textbf{k}}

The cross product \textbf{A}×\textbf{B} is given by

\textbf{A}×\textbf{B} = \left|\begin{array}{ccc}\hat{\textbf{i}} & \hat{\textbf{j}} & \hat{\textbf{k}} \\\:\:5 & -7 & -3 \\ -4 & \:\:4 & -8 \\ \end{array}\right|

=  \left|\begin{array}{cc}-7 & -3\\\:4 & -8\\ \end{array}\right|\:\hat{\textbf{i}}\:+\:\left|\begin{array}{cc}-3 & \:\:5\\-8 & -4\\ \end{array}\right|\:\hat{\textbf{j}}\:+\: \left|\begin{array}{cc}\:\:5 & -7\\-4 & \:\:4\\ \end{array}\right|\:\hat{\textbf{k}}

= 68\hat{\textbf{i}} + 52\hat{\textbf{j}} - 8\hat{\textbf{k}}

5 0
3 years ago
Let x define the position of an object such that x =
timama [110]
See the attached picture for answers

7 0
2 years ago
I've had several mental breakdowns please help me
sesenic [268]

Answer:

The efficiency of the system is 63.7 %

Explanation:

Given;

input power of the motor, = 1.5 kW = 1,500 W

mass of the car lifted, m = 1300 kg

height through which the car was lifted, h = 1.8 m

time, t = 24 s

The output power of the motor is calculated as;

Output Power = F x v

                        = (mg)  x (d/t)

                        = (1300 x 9.8) x (1.8 / 24)

                        = 12,740 x 0.075

                        = 955.5 W

The efficiency of the system is calculated as;

E = \frac{0utput \ power}{1nput \ power} \times \ 100\%\\\\E = \frac{955.5}{1500} \times \ 100\% \\\\E = 63.7 \ \%

The correct answer is 63.7%

4 0
2 years ago
What happens when an object is moved against gravity, such as rolling a toy car up a ramp?
BlackZzzverrR [31]

Answer:

it goes up until we help it to but the moment we stop support it gets affected by gravity and goes back

Explanation:

3 0
2 years ago
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