Answer:
The distance on the screen between the first-order bright fringes for each wavelength is 3.17 mm.
Explanation:
Given that,
Wavelength of red = 660 nm
Wavelength of blue = 470 nm
Separated d= 0.30 mm
Distance between screen and slits D= 5.0 m
We need to calculate the distance for red wavelength
Using formula for distance
Where, D = distance between screen and slits
d = separation of slits
Put the value into the formula
For blue wavelength,
Put the value into the formula again
We need to calculate the distance on the screen between the first-order bright fringes for each wavelength
Using formula for distance
Hence, The distance on the screen between the first-order bright fringes for each wavelength is 3.17 mm.
For this problem, we use the Coulomb's Law whose equation is written as
F = kQ₁Q₂/d²
where
F is the electric force
k is the Coulomb's constant equal to 8.98755×10⁹ N·m²/c²
Q₁ and Q₂ are two charges
d is the distance between two charges
First, let's compute the force between the two positive charges denotes as F₁.
F₁ = (8.98755×10⁹ N·m²/c²)(+53×10⁻⁶ C)(+53×10⁻⁶ C)/(35 cm * 1 m/100cm)²
F₁ = 206.09 N
Next, let's compute the force between the positive and the negative charges denotes as F₂.
F₂ = (8.98755×10⁹ N·m²/c²)(+53×10⁻⁶ C)(-53×10⁻⁶ C)/(35 cm * 1 m/100cm)²
F₂ = -206.09 N
The net force is the sum of the two forces.
Net Force = 206.09 - 206.09 = 0
Therefore, the net force experienced by the positive charge is zero.
Answer:
A) 17.7 m/s
B) 15.98 m
C) Zero
E) 9.8 m/s²
Explanation:
given information
distance, h = - 34 m
time, t = 5 s
A) What is the initial speed of the egg?
h - h₀ = v₀t - t², h₀ = 0
- 34 = v₀ 5 - \frac{1}{2} 9.8 5²
- 34 = 5 v₀ - 122.5
v₀ = 122.5 - 34/5
= 17.7 m/s
B) How high does it rise above its starting point?
v² = v₀² - 2gh
v = 0 (highest point)
2gh = v₀²
h = v₀²/2g
= 17.7²/2 (9.8)
= 15.98 m
C) What is the magnitude of its velocity at the highest point?
v = 0 (at highest point)
E) What are the magnitude and direction of its acceleration at the highest point?
g= 9.8 m/s², since the egg is moved vertically, the acceleration is the same as the gravitational acceleration.
Answer:
It might be like 45-50 mph
Explanation:
Answer:
1. The tension in the rope is everywhere the same.
2. The magnitudes of the forces exerted on the two objects by the rope are the same.
3. The forces exerted on the two objects by the rope must be in opposite directions.
Explanation:
"Massless ropes" do not have a<em> "net force"</em> which means that it is able to transmit the force from one end of the rope to the other end, perfectly. It is known for its property of having a total force of zero. In order to attain this property, the magnitude of the forces exerted on the two stationary objects by the rope are the same and in opposite direction. <u>So this explains number 2 & 3 answers.</u>
Since the objects that are held by the rope are stationary, then this means that the tension in the rope is also stationary. This means that the tension in the rope everywhere is the same (provided that the rope is still or in a straight line, as stated in the situation above, and is being held by two points). <u>So, this explains number 1.</u>