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kkurt [141]
3 years ago
8

When you jump off the earth, your momentum changes, but the Earth does not move. 1)If momentum is always conserved, why do we no

t feel the earth moving every time someone jumps? 2) If we were to get everyone to jump at once, could we change the momentum of the earth?
Physics
1 answer:
Mazyrski [523]3 years ago
8 0

This question is off-base and misleading from the beginning.

When you jump off the Earth, your momentum changes, <em>and the Earth moves away from you with an equal change of momentum in the opposite direction</em>.

1). Momentum is conserved when you jump.  But we don't feel the Earth moving. Since the Earth's mass is a bazillion times greater than YOUR mass, the speed with which the Earth moves away from you is only one bazillionth of your speed.  That way, the product of (mass) x (speed) is the SAME for you and for the Earth, and momentum is conserved.

2). <em>Of course !</em>  If everyone jumped at the same time, the Earth's momentum would change.  In answer-(1), I explained that the Earth's momentum changes whenever <em>ONE PERSON</em> jumps.  So 7 billion people all jumping at the same time would certainly make it change.

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Answer:

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2 years ago
An ice sled powered by a rocket engine starts from rest on a large frozen lake and accelerates at +44 ft/s2. After some time t1,
mash [69]

Answer:

a) t₁ = 4.76 s, t₂ = 85.2 s

b) v = 209 ft/s

Explanation:

Constant acceleration equations:

x = x₀ + v₀ t + ½ at²

v = at + v₀

where x is final position,

x₀ is initial position,

v₀ is initial velocity,

a is acceleration,

and t is time.

When the engine is on and the sled is accelerating:

x₀ = 0 ft

v₀ = 0 ft/s

a = 44 ft/s²

t = t₁

So:

x = 22 t₁²

v = 44 t₁

When the engine is off and the sled is coasting:

x = 18350 ft

x₀ = 22 t₁²

v₀ = 44 t₁

a = 0 ft/s²

t = t₂

So:

18350 = 22 t₁² + (44 t₁) t₂

Given that t₁ + t₂ = 90:

18350 = 22 t₁² + (44 t₁) (90 − t₁)

Now we can solve for t₁:

18350 = 22 t₁² + 3960 t₁ − 44 t₁²

18350 = 3960 t₁ − 22 t₁²

9175 = 1980 t₁ − 11 t₁²

11 t₁² − 1980 t₁ + 9175 = 0

Using quadratic formula:

t₁ = [ 1980 ± √(1980² - 4(11)(9175)) ] / 22

t₁ = 4.76, 175

Since t₁ can't be greater than 90, t₁ = 4.76 s.

Therefore, t₂ = 85.2 s.

And v = 44 t₁ = 209 ft/s.

3 0
2 years ago
A large crane consists of a 20 m, 3,000 kg arm that extends horizontally on top of a vertical tower. The arm extends 15 m toward
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Answer:

m=18000kg

Explanation:

From the question we are told that:

Crane Length l=20m

Crane Mass m_a=3000kg

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Arm extension at counter weight end l_c=5m

Load M_l=5000kg

Generally the equation for Torque Balance is mathematically given by

T_1 *l_c-(m_a*g) *l_c-(T_2)*l_l=0

mg*5 *-(3000*9.8) *5-(5000*9.8)*15=0

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7 0
3 years ago
When a 25-kg crate is pushed across a frictionless horizontal floor with a force of 200 N, directed 20 below the horizontal, th
Fofino [41]

Answer:

Option E is correct 310N

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Given that the force used to push the crate is F = 200N

The force directed 20° below the horizontal

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Weight of the crate can be determine using

W = mg

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W = 25×9.8

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Check attachment. For free body diagram and better understanding

Using newton second law along the vertical axis since we want to find the normal force

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N = W+F•Sin20

N = 245+ 200Sin20

N = 245 + 68.4

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The normal force is approximately 310 N to the nearest ten

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How do you compare the energies of the different parts of the electromagnetic spectrum?
faltersainse [42]

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The energy associated with electromagnetic radiation is proportional to frequency and inversely proportional to wavelength. So, electromagnetic waves with shorter wavelengths have more energy.

On one end of the electromagnetic spectrum are radio waves, which have wavelengths billions of times longer than those of visible light. On the other end of the spectrum are gamma rays with wavelengths billions of times smaller than those of visible light.

To know more about electromagnetic spectrum:

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