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3 years ago

6

Astronomers find a new star in a neighboring galaxy. Which unit of measurement would be used to describe the distance to the sta

r?

1 answer:

Allushta [10]3 years ago

4 0

Answer:

b

Explanation:

^w^

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1. A 14-cm tall object is placed 26 cm from a converging lens that has a focal length of 13 cm.

AURORKA [14]

Answer:

a) Please find attached the required drawing of light passing through the lens

By the use of similar triangles;

The image distance from the lens = 26 cm

The height of the image = 14 cm

c) The image distance from the lens = 26 cm

The height of the image = 14 cm

Explanation:

Question;

a) Determine the image distance and the height of the image

b) Calculate the image position and height

The given parameters are;

The height of the object, h = 14 cm

The distance of the object from the mirror, u = 26 cm

The focal length of the mirror, f = 13 cm

The location of the object = 2 × The focal length

Therefore, given that the center of curvature ≈ 2 × The focal length, we have;

The location of the object ≈ The center of curvature of the lens

The diagram of the object, lens and image created with MS Visio is attached

From the diagram, it can be observed, using similar triangles, that the image distance from the lens = The object distance from the lens = 26 m

The height of the image = The height of the object - 14 cm

b) The lens equation is used for finding the image distance from the lens as follows;

$\dfrac{1}{u} + \dfrac{1}{v} = \dfrac{1}{f}$

Where;

v = The image distance from the lens

We get;

$v = \dfrac{u \times f}{u - f}$

Therefore;

$v = \dfrac{26 \times 13}{26 - 13} = \dfrac{26 \times 13}{13} = 26$

The distance of the image from the lens, v = 26 cm

The magnification, M =v/u

∴ M = 26/26 = 1, therefore, the object and the image are the same size

Therefore;

The height of the image = The height of the object = 14 cm.

5 0

3 years ago

Which of the following statements is/are true? Check all that apply. A. A potential energy function can be specified for a conse

Otrada [13]

Answer:

A. A potential energy function can be specified for a conservative force.

TRUE

because there is no loss of energy in conservative type of forces.

B. A nonconservative force permits a two-way conversion between kinetic and potential energies.

FALSE

It is not true because energy is not conserved in non-conservative forces.

C. The work done by a nonconservative force depends on the path taken.

TRUE

It depends on total path length while in conservative it only depends on initial and final state

D. A potential energy function can be specified for a nonconservative force.

FALSE

Since energy is not stored in non-conservative forces so it is not defined for non conservative forces

E. A conservative force permits a two-way conversion between kinetic and potential energies.

TRUE

Work done against conservative forces is stored in form of potential energy so it is possible to have two way conversion.

F. The work done by a conservative force depends on the path taken.

FALSE

Conservative force work depends only on initial and final state

5 0

4 years ago

How condensation affects the temperature of the area where liquids forms

NISA [10]

Condensation does not effect the temperature of the area, condensation is the product the temperature difference between an object and the area it is in

7 0

3 years ago

A NASA explorer spacecraft with a mass of 1,000 kg takes off in a positive direction from a stationary asteroid. If the velocity

Georgia [21]

Answer: 10000 kg

Explanation:

The momentum $p$ is given by the following equation:

$p=m.V$ (1)

Where:

$m$ is the mass of the object

$V$ is the velocity of the object

Now, in this case and according the conservation of momentum:

$m_{1}v_{1}+m_{2}v_{2}=m_{1}u_{1}+m_{2}u_{2}$ (2)

Where:

$m_{1}=1000kg$ is the mass of the spacecraft

$m_{2}$ is the mass of the asteroid

$v_{1}=0$ is the initial velocity of the spacecraft

$v_{2}=0$ is the initial velocity of the asteroid (because we are told the asteroid is stationary, as the spacracft is on the sateroid it remains stationary as well)

$u_{1}=250m/s$ is the final velocity of the spacecraft

$u_{2}=-25m/s$ is the final velocity of the asteroid

Rewritting (2):

$0=m_{1}u_{1}+m_{2}u_{2}$ (3)

$0=(1000kg)(250m/s)+m_{2}(-25m/s)$ (4)

Finding $m_{2}$ :

$m_{2}=10000kg$ This is the mass of the asteroid

3 0

3 years ago

Read 2 more answers

An increase of 50 dB increases the sound intensity by a factor of

Artemon [7]

A factor of 50dB = a factor of 10^(50/10) = 10^5 = a factor of <em>100,000</em> .

5 0

4 years ago