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Solnce55 [7]
4 years ago
5

Which of the following statements is/are true? Check all that apply. A. A potential energy function can be specified for a conse

rvative force. B. A nonconservative force permits a two-way conversion between kinetic and potential energies. C. The work done by a nonconservative force depends on the path taken. D. A potential energy function can be specified for a nonconservative force. E. A conservative force permits a two-way conversion between kinetic and potential energies. F. The work done by a conservative force depends on the path taken.
Physics
1 answer:
Otrada [13]4 years ago
5 0

Answer:

A. A potential energy function can be specified for a conservative force.

TRUE

because there is no loss of energy in conservative type of forces.

B. A nonconservative force permits a two-way conversion between kinetic and potential energies.

FALSE

It is not true because energy is not conserved in non-conservative forces.

C. The work done by a nonconservative force depends on the path taken.

TRUE

It depends on total path length while in conservative it only depends on initial and final state

D. A potential energy function can be specified for a nonconservative force.

FALSE

Since energy is not stored in non-conservative forces so it is not defined for non conservative forces

E. A conservative force permits a two-way conversion between kinetic and potential energies.

TRUE

Work done against conservative forces is stored in form of potential energy so it is possible to have two way conversion.

F. The work done by a conservative force depends on the path taken.

FALSE

Conservative force work depends only on initial and final state

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Answer:

The center of mass of the two-ball system is 7.05 m above ground.

Explanation:

<u>Motion of 0.50 kg ball:</u>

Initial speed, u = 0 m/s

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Substituting in equation s = ut + 0.5 at²

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<u>Motion of 0.25 kg ball:</u>

Initial speed, u = 15 m/s

Time = 2 s

Acceleration = -9.81 m/s²

Substituting in equation s = ut + 0.5 at²

                 s = 15 x 2 - 0.5 x 9.81 x 2² = 10.38 m

Height above ground = 10.38 m

We have equation for center of gravity

          \bar{x}=\frac{m_1x_1+m_2x_2}{m_1+m_2}

          m₁ = 0.50 kg

          x₁ = 5.38 m        

          m₂ = 0.25 kg

          x₂ = 10.38 m    

Substituting

         \bar{x}=\frac{0.50\times 5.38+0.25\times 10.38}{0.50+0.25}=7.05m

The center of mass of the two-ball system is 7.05 m above ground.  

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When you ask for "joules per second", you're asking for "watts".
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Electrical power = (voltage) x (current) =

                              (6 volts) x (0.5 ampere) =

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You set your stationary bike on a high 80-N friction-like resistive force and cycle for 30 min at a speed of 8.0 m/s . Your body
stellarik [79]

A) The change in internal chemical energy is 1.15\cdot 10^7 J

B) The time needed is 1 minute

Explanation:

First of all, we start by calculating the power output of you and the bike, given by:

P=Fv

where

F = 80 N is the force that must be applied in order to overcome friction and travel at constant speed

v = 8.0 m/s is the velocity

Substituting,

P=(80)(8.0)=640 W

The energy output is related to the power by the equation

P=\frac{E}{t}

where:

P = 640 W is the power output

E is the energy output

t = 30 min \cdot 60 = 1800 s is the time elapsed

Solving for E,

E=Pt=(640)(1800)=1.15\cdot 10^6 J

Since the body is 10% efficient at converting chemical energy into mechanical work (which is the output energy), this means that the change in internal chemical energy is given by

\Delta E = \frac{E}{0.10}=\frac{1.15\cdot 10^6}{0.10}=1.15\cdot 10^7 J

B)

From the previous part, we found that in a time of

t = 30 min

the amount of internal chemical energy converted is

E=1.15\cdot 10^7 J

Here we want to find the time t' needed to convert an amount of chemical energy of

E'=3.8\cdot 10^5 J

So we can setup the following proportion:

\frac{t}{E}=\frac{t'}{E'}

And solving for t',

t'=\frac{E't}{E}=\frac{(3.8\cdot 10^5)(30)}{1.15\cdot 10^7}=1 min

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brainly.com/question/7956557

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