Answer:
4.2 A
Explanation:
V=IR
V= voltage
I= Current
R= resistance
so you will find the resistance in the circuit so
R= V/I
R=2V/0.70A
R=2.857 ohms ( TO THE NEAREST THOUSANDTH)
then you will find the current of the 12V battery using the resistance in the circuit
I=V/R
I=12/2.857
I=4.2A (TO THE NEAREST TENTH)
The answer is <span> A. Yes, the wave will transfer the energy of Amy's motion to the other end of the rope.</span>
Answer:
The object displacement is 0 meters.
Explanation:
Because the expression for the object position as function of time is:
At t= 3.0=t2 seconds the x-position of the object is:
and at t=1.0=t1 seconds the x-position of the objects is:
The total displacement () of the object between t2 and t1 is the difference between x(3.0s) and x(1.0s):
The displacement of the object is zero!!!
Answer:
x₂ / x₁ = √2
Explanation:
To solve this exercise we can use the projectile launch ratios, let's find the time it takes for the second book to reach the ground
y = y₀ + t - ½ g t²
as the book is thrown horizontally v_{oy} = 0, when it reaches the ground its height is zero y= 0
0 = y₀ - ½ g t²
t =
t = \sqrt{ \frac{2 \ 2h}{ g} }
with this time we calculate the horizontal distance traveled
x = v₀ t
x₂ = v₀
now let's calculate the time it takes him to get to the floor when he leaves from the first floor
t =\sqrt{ \frac{2y_o}{ g} }
the horizontal distance traveled is
x₁ = v₀
therefore the difference in distance between the two runs is
Δx = x₂-x₁
Δx = v₀ \sqrt{ \frac{4h}{g} } - v₀ \sqrt{ \frac{2h}{g} }
Δx = v₀ \sqrt{ \frac{2h}{g} } √2
Δx =√2 x₁
the relationship between the two distances is
x₂ / x₁ = √2
Answer: B=1.92nT
Explanation:This question uses the Biot-Savart law: the law is an equation that describes the magnetic field created by a current-carrying wire, and allows you to calculate its strength at various points.
B=(μ0/4*π)*q*v*r(unit vector)/r²
Also:
B=(μ0/4*π)*q*v*sin(θ)/r²
Where;
μ0 =permeability of free space = 4πx10-7 Hm-1
B = magnetic field in Tesla
V= velocity
r= radius
Therefore:
B=(4πx10-7/4*π)*q*v*sin(θ)/r^2
B=1x10-7*q*v*sin(θ)/r^2
Using:
q=15x10-3C
v=40m/s
tan(θ)=5/2 so θ=68.2°
r²=5²+2² (Pythagoras Theorem)
B can be calculated as:
B=1x10-7*15x10-3*40*sin(68.2)/(5²+2²)
B=1.92nT