Written in scientific notation, to three significant digits, the number 699 875 is_______?_____

Which type of wave can travel through enpty space? EXPLAIN.

jok3333 [9.3K]

Answer:

Electromagnetic waves carry energy.

Explanation:

The waves consist of transverse vibrations in electrical and magnetic fields, not vibrating particles.

6 0

3 years ago

A charge of uniform volume density (40 nC/m3) fills a cube with 8.0-cm edges. What is the total electric flux through the surfac

GREYUIT [131]

Answer:

The flux through the surface of the cube is $2.314\ Nm^{2}/C$

Solution:

As per the question:

Edge of the cube, a = 8.0 cm = $8.0\times 10^{- 2}\ m$

Volume Charge density, $\rho_{v} = 40 nC/m^{3} = 40\times {- 9}\ C/m^{3}$

Now,

To calculate the electric flux:

$\phi = \frac{q}{\epsilon_{o}}$ (1)

where

$\phi$ = electric flux

$\epsilon_{o} = 8.85\times 10^{- 12}\ F/m$ = permittivity of free space

Volume Charge density for the given case is given by the formula:

$\rho_{v} = \frac{Total\ charge, q}{Volume of cube, V}$ (2)

Volume of cube, $V = a^{3}$

Thus

$V = (8.0\times 10^{- 2})^{3} = 5.12\times 10^{- 4}\ m^{3}$

Thus from eqn (2), the total charge is given by:

$q = \rho_{v}V = 40\times {- 9}\times 5.12\times 10^{- 4}$

$q = 2.048\times 10^{-11}\ F = 20.48\ pF$

Now, substitute the value of 'q' in eqn (1):

$\phi = \frac{2.048\times 10^{-11}}{8.85\times 10^{- 12}} = 2.314\ Nm^{2}/C$

5 0

3 years ago

If constants aren't given in an experiment, what can be constant in the experiment?

mario62 [17]

Answer:

Anything in an experiment that remains unchanged.

Explanation:

An example could be the temperature of the laboratory room. If there is something that has an effect on an experiment that is not variable, it is a constant. Another constant could be, say, if you were doing calculations with the same amount and kind of fluid throughout the experiment, then that fluid would also be a constant.

6 0

3 years ago

What is a wave that has all the crests and troughs in the same place at the same time?

slega [8]

Wavelength
is the answer

3 0

3 years ago

Read 2 more answers

The difference in potential between the accelerating plates of a TV set is about 24 kV. The distance between these plates is 1.5

ryzh [129]

Answer:

So electric field between the plates will be equal to $1600\times 10^3KN/C$