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finlep [7]
4 years ago
14

Written in scientific notation, to three significant digits, the number 699 875 is_______?______ x 10?

Physics
1 answer:
mojhsa [17]4 years ago
8 0

.699875 x10  {}^{6}
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With what tension must a rope with length 2.90 m and mass 0.125 kg be stretched for transverse waves of frequency 42.0 Hz to hav
Vesnalui [34]

Answer:

41.64 N

Explanation:

Applying,

v = √(T/m')................ Equation 1

Where v = velocity of the wave, T = Tension of the rope, m' = mass per unit length of the rope.

make T the subject of the equation,

T = v²m'................. Equation 2

But,

v = λf............... Equation 3

Where λ = wavelength, f = frequency

And

m' = m/L........... Equation 4

Where m = mass of the rope, L = length of the rope

Substitute equation 3 and equation 4 into equation 2

T = (λf)²(m/L).............. Equation 5

From the question,

Given: λ = 0.740 m, f = 42 Hz, m = 0.125 kg, L = 2.9 m

Substitute these values into equation 5

T = (42×0.74)²(0.125/2.9)

T = 41.64 N

6 0
3 years ago
At a given instant in time, two cars are traveling at different velocities, one twice as large as the other. Based on this infor
Sati [7]

Answer: No, is not possible.

Explanation:

We have two cars traveling at different velocities, one with velocity v and other with velocity 2*v

We want to know of it is possible to say which of these two cars has the larger acceleration at this instant of time.

Acceleration is the rate of change of the velocity, for example, if acceleration = 0, the velocity does not change.

Notice that knowing only the velocity at a given instant of time, we do not have any way of knowing the acceleration of each car.

Such that acceleration is given by the second Newton's equation:

F = m*a

force equals mass times acceleration.

We do not know any of these quantities for the cars, so we can not say anything about the accelerations.

We also could know the average acceleration if we know the change in velocity over an interval of time, such that:

Av acceleration = (change in velocity)/(interval of time)

But here we do not have a change in velocity, so again, we can't say anything about the acceleration.

3 0
3 years ago
A Venturi tube may be used as a fluid flowmeter. Suppose the device is used at a service station to measure the flow rate of gas
leonid [27]

Answer

given,

flow rate = p = 660 kg/m³

outer radius = 2.8 cm

P₁ - P₂ = 1.20 k Pa

inlet radius = 1.40 cm

using continuity equation

 A₁ v₁ = A₂ v₂

 π r₁² v₁ = π r₁² v₂

 v_1= \dfrac{r_1^2}{r_2^2} v_2

 v_1= \dfrac{1.4^2}{2.8^2} v_2

 v_1= 0.25 v_2

Applying Bernoulli's equation

 \Delta P = \dfrac{1}{2}\rho (v_2^2-v_1^2)

 \Delta P = \dfrac{1}{2}\rho (v_2^2-(0.25 v_2)^2)

 \Delta P = \dfrac{1}{2}\rho v_2^2 (1 - 0.0625)

 v_2=\sqrt{\dfrac{2\Delta P}{\rho(1 - 0.0625)}}

 v_2=\sqrt{\dfrac{2\times 1200}{660 \times(1 - 0.0625)}}

       v₂ = 1.97 m/s

b) fluid flow rate

Q = A₂ V₂

Q = π (0.014)²  x 1.97

Q = 1.21 x 10⁻³ m³/s

5 0
4 years ago
Which protects a cell and forms it’s boundary
ivann1987 [24]

Answer:

For a plant cell: The cell wall and the cell membrane

For animal cells: Just the cell membrane

5 0
3 years ago
Matt plays badminton. He serves the birdie with a velocity of 4.25 m/s [right] covering a displacement of 5.2 m [forward]. How m
OLEGan [10]

Answer:

Time taken by birdie’s trip = 1.2235 s (Approx)

Explanation:

Given:

Velocity = 4.25 m/s

Displacement = 5.2 m

Find:

Time taken by birdie’s trip = ?

Computation:

⇒ Time taken = Displacement / Velocity

⇒ Time taken by birdie’s trip = Displacement / Velocity

⇒ Time taken by birdie’s trip = 5.2 m / 4.25 m/s

⇒ Time taken by birdie’s trip = 1.2235 s (Approx)

6 0
3 years ago
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