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Kay [80]
2 years ago
11

Which describes how sliding friction affects pushing a cereal box across a tabletop?

Physics
2 answers:
elena55 [62]2 years ago
6 0

The term sliding friction refers to the resistance created by two objects sliding against each other. This can also be called kinetic friction. Sliding friction is intended to stop an object from moving.

Understanding Sliding Friction

The amount of sliding friction created by objects is expressed as a coefficient which takes into consideration the various factors that can affect the level of friction. These various factors that can impact sliding friction include the following:

The surface deformation of objects

The roughness/smoothness of the surface of the objects

The original speed of either object

The size of object

The amount of pressure on either object

The adhesion of the surface

So from the above options correct answer must be

<u>It acts in the direction opposite of motion.</u>

Vinil7 [7]2 years ago
5 0
I think your best bet would be.

It acts in the direction opposite of the motion
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To solve this problem we will use the linear motion kinematic equations, for which the change of speed squared with the acceleration and the change of position. The acceleration in this case will be the same given by gravity, so our values would be given as,

m= 89 kg\\x = 3.1 m\\t = 0.5s\\a = g = 9.8m/s^2

Through the aforementioned formula we will have to

v_f^2-v_i^2 = 2ax

The particulate part of the rest, so the final speed would be

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v_f=\sqrt{2(9.8)(3.1)}

v_f = 7.79m/s

Now from Newton's second law we know that

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Here,

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F = m\frac{dv}{dt}

Replacing we have that,

F = (89)\frac{7.79}{0.5}

F = 1386.62N

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3 0
3 years ago
You go to the hardware store to buy a new 50 ft garden hose. You find you can choose between hoses of ½ inch and 5/8 inch inner
omeli [17]

To solve this problem it is necessary to consider two concepts. The first of these is the flow rate that can be defined as the volumetric quantity that a channel travels in a given time. The flow rate can also be calculated from the Area and speed, that is,

Q = V*A

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The second concept related to the calculation of this problem is continuity, which is defined as the proportion that exists between the input channel and the output channel. It is understood as well as the geometric section of entry and exit, defined as,

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Our values are given as,

A_1=\frac{1}{2}^2*\pi=0.785 in^2

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Re-arrange the equation to find the first ratio of rates we have:

\frac{V_1}{V_2}=\frac{A_2}{A_1}

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\frac{V2}{V1}=\frac{A_1}{A2}

\frac{V2}{V1}=\frac{0.785}{1.227}

\frac{V2}{V1}=0.640

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