Answer: X=1
Step-by-step explanation:
The hypotenuse is √2 which means that x²+x²=(√2)² using Pythagoras
Simplify and solve
2x²=2
x²=1
X=√1
X=1
Question:
The quantities x and y are proportional.
x y
5.8 7.5
11.2
Find the constant of proportionality (r) in the equation y=rx
Answer:
The constant of proportionality is 75/58 or 1.29
Step-by-step explanation:
Given
The table above
Required
Find the constant of proportionality
The question has an incomplete table but it can still be solved because x and y are proportional.
Given that
y = rx
Make r the subject of formula
Divide through by x
y/x = rx
y/x = r
r = y/x
When y = 7.5, x = 5.8
Substitute these values
r = y/x becomes
r = 7.5/5.8
Multiply denominator and numerator by 10
r = (7.5 * 10)/(5.8 * 10)
r = 75/58
In this case, it's best to leave the answer in fraction.
However, it can be solved further.
r = 75/58
r = 1.29 (Approximated)
Hence, the constant of proportionality is 75/58 or 1.29
Answer:
C. 4,100
Step-by-step explanation:
"60% more" is represented by a multiplier of 1 + 0.60 = 1.60.
"60% fewer" is represented by a multiplier of 1 - 0.60 = 0.40.
__
Let b represent the number of booklets distributed by Team B. Then the number distributed by Team A is ...
1.60 × (0.40b) . . . . 60% more boxes, each with 60% fewer booklets
= 0.64b
Then the total distributed by both teams is ...
b + 0.64b = 1.64b = (164/100)b = (41/25)b
The only answer choice that is a multiple of 41 is ...
4,100 . . . choice C
__
For 4100 to be the number of booklets distributed by both teams, Team B will have distributed 2500 booklets, and Team A will have distributed 1600 booklets. Team A might have distributed 160 boxes of 100 booklets, while Team B might have distributed 100 boxes of 250 booklets.
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Answer:
we know that, Volume of cube=a³
Let volume of 1st cube be 2x with side a and other be x with side A (according to given ratio)
Step-by-step explanation:
ATQ: 2x=a³ and, x=A³
a=³√2x and, A=x
we know that, surface area of cube is 6a²
Thus, surface area of 1st cube = 6(³√2x)²
= 6³√4x²
Surface area of 2nd cube=6(x)²=6x²
Ratio of S.A=(6³√4x²)÷(6x²)
Ratio of S.A=³√4:1
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