Answer:
The balance point is the,number in between your set of numbers so you need to find The middle of 3 and 7, and then when you get that answer you find the number in between 8 and the,number you just found
Step-by-step explanation:
I'm not good at figuring this out myself but, I know the steps
Answer:
17.2
Step-by-step explanation:
3x=12+y
x=12+y/3
![8( \frac{12 + y}{3}) \div 2y](https://tex.z-dn.net/?f=8%28%20%20%5Cfrac%7B12%20%2B%20y%7D%7B3%7D%29%20%5Cdiv%202y)
![\frac{96 + 8y}{3} \times \frac{1}{2y}](https://tex.z-dn.net/?f=%20%5Cfrac%7B96%20%2B%208y%7D%7B3%7D%20%5Ctimes%20%20%5Cfrac%7B1%7D%7B2y%7D%20)
![\frac{96 + 8y}{6y}](https://tex.z-dn.net/?f=%20%5Cfrac%7B96%20%2B%208y%7D%7B6y%7D%20)
(y is divided by y so it no longer exists)
![\frac{96 + 8}{6}](https://tex.z-dn.net/?f=%20%5Cfrac%7B96%20%2B%208%7D%7B6%7D%20)
![\frac{104}{6}](https://tex.z-dn.net/?f=%20%5Cfrac%7B104%7D%7B6%7D%20)
![17.2](https://tex.z-dn.net/?f=17.2)
Answer:
1. B. interior
2. C. equilateral
Step-by-step explanation:
Yes, it is possible as shown in the picture attached. There are two lines which are different functions. They intersect at one x-intercept. As the two lines extend infinitely at both ends, their domains and ranges are from ∞ to +∞. Therefore, the two functions drawn as two lines, have an identical x-intercept, domain and range.