The total number of protons in this atom is 79 because an atomic number of an element is equal to the number of protons. Here, the atomic number is 79 after adding the given electronic configuration.
What are Protons?
Every atom has a proton, a subatomic particle, in its nucleus. The particle possesses an electrical charge that is positive and opposite to the electrons.
What is Atom?
A nucleus plus one or more electrons bound to the nucleus make up an atom. The quantity of protons or electrons in an element's atom determines how different it is from other similar elements. The atomic number of an element, which serves as its primary identification, is the sum of its protons or electrons.
What is Electronic configuration?
The arrangement of electrons in atomic or molecular orbitals within an atom, molecule, or other physical structure is known as the electron configuration.
Hence, the total number of protons in this atom is 79, after adding 2 + 8 + 18 + 32 + 18 + 1.
To know more about Atom, check out:
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Answer:
In 1 mol of Pb₃(PO₄)₄ occupies 1001.48 grams
Explanation:
This compound is the lead (IV) phosphate.
Grams that occupy 1 mole, means the molar mass of the compound
Pb = 207.2 .3 = 621.6 g/m
P = 30.97 .4 = 123.88 g/m
O = (16 . 4) . 4 = 256 g/m
621.6 g/m + 123.88 g/m + 256 g/m = 1001.48 g/m
<span>Same answer, different setup. We know that the sum of the oxidation numbers is zero for a compound and the ionic charge for a polyatomic ion, and we know that sulfite ion is -2.
Create an algebraic equation by multiplying the subscripts times the oxidation number of a single element.
+x -6 = -2
+x -2
S O3
Solve for x
x = +4</span>
"As we move through the visible spectrum of violet, blue, green, yellow, orange and red, the wavelengths become longer. The range of wavelengths (400 - 700 nm) of visible light is centrally located in the electromagnetic spectrum (Fig. 1)."
-https://www.asu.edu/courses/phs208/patternsbb/PiN/rdg/color/color.shtml
Answer:
The answer is "Option C".
Explanation:
Please find the complete question and its solution in the attached file.
using Hoffman's elimination reaction.
