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ruslelena [56]
3 years ago
15

Classify each of the molecules given below by molecular shape.

Chemistry
1 answer:
maw [93]3 years ago
4 0
Missing question find on internet.
Answers are:
1) O₂ - linear.
2) CH₄ - tetrahedral.
3) SO₃ - t<span>rigonal planar.
4) SF</span>₄ - <span>trigonal bipyramidal.
5) BeF</span>₂ - linear.
6) SiCl₄ - <span>tetrahedral.
7) ClF</span>₃ - <span>T-shaped.</span><span>
8) CO</span>₂ - linear.
9) NH₃ - <span>trigonal pyramidal.
10) SO</span>₂ - bent.
11) H₃O⁺ - <span>trigonal pyramidal.
12) XeF</span>₄ - <span>square planar.
13) H</span>₂O - bent.

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In the compound CO2, how many lone pairs are on the central atom?
Cloud [144]
There are 4 lone pairs of electrons present in the carbon dioxide molecule 
4 0
3 years ago
If 20.0 g of NaOH is added to 0.750 L of 1.00 M Cd(NO₃)₂, how many grams of Cd(OH)₂ will be formed in the following precipitatio
bulgar [2K]

Answer:

m_{Cd(OH)_2}=36.6 gCd(OH)_2

Explanation:

Hello.

In this case, for the given chemical reaction, in order to compute the grams of cadmium hydroxide that would be yielded, we must first identify the limiting reactant by computing the yielded moles of that same product, by 20.0 grams of NaOH (molar mass = 40 g/mol) and by 0.750 L of the 1.00-M solution of cadmium nitrate as shown below considering the 1:2:1 mole ratios respectively:

n_{Cd(OH)_2}^{by\ NaOH}=20.0gNaOH*\frac{1molNaOH}{40gNaOH} *\frac{1molCd(OH)_2}{2molNaOH} =0.25molCd(OH)_2\\\\n_{Cd(OH)_2}^{by\ Cd(NO_3)_2}=0.750L*1.00\frac{molCd(NO_3)_2}{L}*\frac{1molCd(OH)_2}{1molCd(NO_3)_2}  =0.75molCd(OH)_2

Thus, since 20.0 grams of NaOH yielded less of moles of cadmium hydroxide, NaOH is the limiting reactant, therefore the mass of cadmium hydroxide (molar mass = 146.4 g/mol) is:

m_{Cd(OH)_2}=0.25molCd(OH)_2*\frac{146.4gCd(OH)_2}{1molCd(OH)_2} \\\\m_{Cd(OH)_2}=36.6 gCd(OH)_2

Best regards.

4 0
3 years ago
A 4,000 mL solution of AgNO3 contains 17.00 g of solute in water. Calculate the molar concentration of the solution.
blsea [12.9K]
The molarity is moles/liters.

First, convert 4,000 mL to L:

4000 mL --> 4 L

Now, you must convert the 17 g of solute to moles by dividing the number of grams by the molar mass. The molar mass of AgNO3 is <span>169.87 g/mol:

17 / 169.87 = .1

Now that you have both the number of moles and the liters, plug them into the initial equation of moles/liters:

.1/4 = .025</span>
3 0
3 years ago
Read 2 more answers
PLSSSSS HELPPPP......
rosijanka [135]
Answer: A

Explanation:
The buoyancy force only takes affect when an object is placed in water and floats. This occurs because the density of that object is less than the density of water.
Water is the main liquid used for measuring the density of an object.

Hope this helps! Please tell me if I am wrong :3
7 0
3 years ago
Helppppppppppppppppp​
vovangra [49]
Do not trust people that share links these people hack and put viruses. to your phone/computer’s


DO NOT TRUST THESE LINKS
7 0
3 years ago
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