Question

If the rate of formation (also called rate of production) of compound C is 2M/s in the reaction A --->2C, what is the rate of consumption of A

Answer 1

Answer:

$r_A=-1\frac{M}{s}$

Explanation:

Hello,

In this case, given the rate of production of C, we can compute the rate of consumption of A by using the rate relationships which include the stoichiometric coefficients at the denominators (-1 for A and 2 for C) as follows:

$\frac{1}{-1} r_A=\frac{1}{2}r_C$

In such a way, solving the rate of consumption of A, we obtain:

$r_A=-\frac{1}{2} r_C=-\frac{1}{2}*2\frac{M}{s}\\ \\r_A=-1\frac{M}{s}$

Clearly, such rate is negative which account for consumption process.

Regards.