<img src="https://tex.z-dn.net/?f=%20%5Clarge%7B%5Cbold%20%5Cred%7B%20%5Csum%20%5Climits_%7B8%7D%5E%7B4%7D%20%7Bx%7D%5E%7B2%7D%2

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2 years ago

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0%2B%209%28%20%5Cfrac%7B%20%5Ccos%5E%7B2%7D%5Cinfty%20%7D%7B%20%7B%20%5Csin%7D%5E%7B2%7D%20%5Cinfty%20%7D%20%29%7D%7D" id="TexFormula1" title=" \large{\bold \red{ \sum \limits_{8}^{4} {x}^{2} + 9( \frac{ \cos^{2}\infty }{ { \sin}^{2} \infty } )}}" alt=" \large{\bold \red{ \sum \limits_{8}^{4} {x}^{2} + 9( \frac{ \cos^{2}\infty }{ { \sin}^{2} \infty } )}}" align="absmiddle" class="latex-formula">
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2 answers:

RSB [31]2 years ago

8 0

Answer:

i dont know what is this

Step-by-step explanation:

max2010maxim [7]2 years ago

6 0

Answer:

how did u do that the infinite thing

Step-by-step explanation:

h o w

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Which of the following lists of ordered pairs is a function?

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To find if one is a function, you must see if the pattern is the same.
Domains (x) can not have two values
I forget what the y value is called, but there can be the same y- value for multiple x - values

A. is not a function, because its ordered pairs are all over the place, and the value 4 in the x - value has two values assigned - 0 and 3, which makes it invalid.

B. may be a linear function. Its ordered pairs aren't jumping all over the place.
Both the x and y go up one for one, so the function could be y = x + 3

C. isn't because the x - value 2 has two values. Again, that makes this invalid.

D. is invalid because there is two x - values for 2.

Therefore, the answer is B.

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3 years ago

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What is 5 multiplied by 2

koban [17]

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Step-by-step explanation:

5x2 to me is basically adding 5 twice.

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5x2=10

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3 years ago

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At another theater, workers have to cut a new trap door. The door can be no more than 137 square feet in area, with whole-number

otez555 [7]

Answer:

Step-by-step explanation:

Given:

trap door = 130 square feet.

1st item: 6ft 5in wide & 8ft 9in long

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2 years ago

Can someone pretty please help me on these two questions

mamaluj [8]

What is the original one of the graphs?

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3 years ago

Suppose r⃗ (t)=cos(πt)i+sin(πt)j+5tkr→(t)=cos(πt)i+sin(πt)j+5tk represents the position of a particle on a helix, where zz is th

gtnhenbr [62]

Answer:

a) t = 4

b) v = pi j + 5 k

c) rt = 1i + (pi t) j + (20 +5t )k

Step-by-step explanation:

You have the following vector equation for the position of a particle:

$r(t)=cos(\pi t)\hat{i}+sin(\pi t)\hat{j}+5t\hat{k}$ (1)

(a) The height of the helix is given by the value of the third component of the position vector r, that is, the z-component.

For a height of 20 you have:

$5t=20\\\\t=\frac{20}{5}=4$

(b) The velocity of the particle is the derivative, in time, of the vector position:

$v(t)=\frac{dr(t)}{dt}=-\pi sin(\pi t)\hat{i}+\pi cos(\pi t)\hat{j}+5\hat{k}$ (2)

and for t=4 (height = 20):

$v(t=4)=-\pi sin(\pi (4))\hat{i}+\pi cos(\pi (4))\hat{j}+5\hat{k}\\\\v(t=4)=-0\hat{i}+\pi\hat{j}+5\hat{k}$

(c) The vector parametric equation of the tangent line is given by:

$r_t(t)=r_o+vt$ (3)

ro: position of the particle for t=4

$r_o=cos(\pi (4))\hat{i}+sin(\pi (4))\hat{j}+20\hat{k}\\\\r_o=\hat{i}+0\hat{j}+20\hat{k}$

Then you replace ro and v in the equation (3):

$r_t=(1\hat{i}+20\hat{k})+(\pi \hat{j}+5\hat{k})t\\\\r_t=1\hat{i}+\pi t \hat{j}+(20+5t)\hat{k}$

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3 years ago