Answer:
The usually speed of the bus is 50 miles/h.
Step-by-step explanation:
Let the usual speed of the bus be x mile/hour.
We know that
The bus travels 200 miles.
To reach its destination it takes time 
h
This week however the bus leaves at 5:40.
The bus late 40 minutes 
Now the speed of the bus is = (x+10) miles/h
The new time to reach the destination is 
h
According to the problem,
![\Rightarrow 200[\frac{x+10-x}{x(x+10)}]=\frac{2}{3}](https://tex.z-dn.net/?f=%5CRightarrow%20200%5B%5Cfrac%7Bx%2B10-x%7D%7Bx%28x%2B10%29%7D%5D%3D%5Cfrac%7B2%7D%7B3%7D)
![\Rightarrow 200[\frac{10}{x^2+10x}]=\frac{2}{3}](https://tex.z-dn.net/?f=%5CRightarrow%20200%5B%5Cfrac%7B10%7D%7Bx%5E2%2B10x%7D%5D%3D%5Cfrac%7B2%7D%7B3%7D)
⇒2(x²+10x)=200×10×3
⇒x²+10x = 3000
⇒x²+10x -3000=0
⇒x²+60x-50x-3000=0
⇒x(x+60)-50(x+60)=0
⇒(x+60)(x-50)=0
⇒x= -60,50
∴x=50 [since speed does not negative]
The usually speed of the bus is 50 miles/h.
Boys: x
gilrs: y
From the text of the task:
Replacing x:
So there are 28 girs and 20 boys
4x - 5
Or what kind of an answer are you looking for?
Answer:
- <u><em>The volume of Carly's cube is 125 in³</em></u>
Explanation:
The volume of a cube is calculated as the length of the side raised to the cube:
<u>1. Cube drawn by Owen</u>
From the drawing:
<u>2. Cube drawn by Pat</u>
Side length is 3 units greater than the side length of Owen’s cube:
<u>3. Cube drawn by Carly</u>
Side length is 1/2 the side length of Pat’s cube:
- Side = (1/2) × 10 in = 5 in
- Volume = (5 in)³ = 125 in³
The formula for the area of a triangle of base b and altitude h is A = (1/2)(b)(h).
Here, b = 18 cm and h = 9 cm. Thus, the desired area is:
(18 cm)(9 cm)
A = ----------------------- = 81 cm^2
2
This problem gives you more info than is needed to solve it. The area of the given triangle is 81 cm^2.
