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timama [110]
3 years ago
12

Lee conducts an experiment to see if mass is conserved when a piece of charcoal is burned for 5.0 minutes. He measures the mass

of the charcoal before lighting it with a match. At the end of 5.0 minutes, Lee puts out the fire by suffocating it. After the charcoal has cooled, he measures its mass again. His data are below.
Initial Mass | Final Mass
.415 | .289

Charlene tries to repeat Lee's experiment by using a different piece of charcoal. But she burns the charcoal for just 3.0 minutes and collects all of the gas and dust released by the burning charcoal. She then weighs the total mass of these objects. Her results are below.
Initial Mass | Final Mass
.498 | .498
Charlene's experimental results indicate that mass was conserved. Why do Lee's results indicate that mass was not conserved?

He burned the charcoal for a longer period of time than Charlene did.

He did not collect the gas and dust released by the burning charcoal.

He forgot to measure the mass of the charcoal while it was still burning.

Mass is not conserved when an object undergoes a chemical change.
Chemistry
1 answer:
strojnjashka [21]3 years ago
3 0
Charlene conserves mass by collecting "the gas and dust released by the burning charcoal", and Lee does not . . . so the answer is . .

<u><em> . . . He did not collect the gas and dust released by the burning charcoal.</em></u>
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The [-oh) in a sample of egg whites is 6.3 x 10-7 m. what is the [h3o+] in these<br>egg whites?
Kamila [148]

The hydrogen ion concentration [H3O+] in an egg white containing 6.3 × 10-⁷M of [OH-] is 1.5 × 10-⁸M.

<h3>How to calculate [H3O+]?</h3>

The hydrogen ion concentration of a solution can be calculated as follows:

pOH = - log [OH-]

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Therefore, the hydrogen ion concentration [H3O+] in an egg white containing 6.3 × 10-⁷M of [OH-] is 1.5 × 10-⁸M.

Learn more about hydrogen ion concentration at: brainly.com/question/15082545

7 0
1 year ago
What is the pH of pure water at 40.0°C if the Kw at this temperature is 2.92 - 10-147 OA) 6.767 O B) 0 465 O c) 7.000 OD) 7 233
Sergeeva-Olga [200]

Answer:

PH= 6.767     (answer is the A option)

Explanation:

first we need to correct the value in Kw at this temperature is 2.92*10^-14

so, in this case we have that:

Kw=2.92*10^-14 M²

[ H3O^+] [ H3O^+]

[H_{3}O^{+}  ] [OH^{-}  ] = Kw = 2.92*10^{-14} M^{2}   \\\\

at 40ºC

[H_{3}O^{+}  ] = [OH^{-}  ]

[H_{3}O^{+}  ]^{2} = 2.92*10^{-14} M^{2}

[H_{3}O^{+}  ] = (2.92*10^{-14})^{1/2} = 1.71*10^{-7} M

PH= -log10[H_{3}O^{+}  ] = -log10(1.71*10^{-7} ) = 6.767

7 0
2 years ago
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