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maks197457 [2]
3 years ago
13

For the following reaction, identify the element that was oxidized, the element that was reduced, and the reducing agent. Give a

n explanation for each answer. . 2CO + 2NO yields 2CO2 + N2
Chemistry
1 answer:
Volgvan3 years ago
6 0

<span>For this reaction, oxidation number of Carbon in CO would be +2 while oxidation number of carbon in CO2 would be +4 and so this means that carbon has oxidized. Oxidation number of nitrogen in NO is +2. While oxidation number of nitrogen in N2 is 0 so this means that nitrogen had reduced. The reducing agent is the one which provides electrons by oxidizing itself so in this case; CO is the reducing agent while the C in CO oxidized to produce electrons. </span><span>I am hoping that this answer has satisfied your query about and it will be able to help you, and if you’d like, feel free to ask another question.</span>

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For the homogeneous solution, consisting of kcl and h2o, indicate the type of forces that are involved.
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4 0
3 years ago
12. A voltaic cell consists of a chromium electrode dipped in a 1.20 M chromium (III) nitrate
Lilit [14]

For a voltaic cell consisting of chromium, an electrode dipped in a 1.20 M chromium (III) nitrate solution and a tin electrode dipped in a 0.400 M tin (II) nitrate solution, the cell potential at 298 K  is mathematically given as

Ecell = 0.577 V

<h3 /><h3>What is the cell potential at 298 K?</h3>

Generally, the equation for the Oxidation and Reduction  is mathematically given as

Cr(s) ------------------ Cr+3(aq) + 3e- ] x 2 ...O

Sn+2(aq) + 2e- ------------ Sn(s) ] x 3  ...R

Reaction

 2 Cr(s) + 3 Sn+2(aq) --------------- 2 Cr+3(aq) + 3 Sn(s)

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Eicell = 0.60

In conclusion

Ecell= E0cell - \frac{0.0591}{n} * \frac{log[Cr+3]^2}{ [ Sn+2]^3}

Ecell = 0.60 - \frac{0.0591 }{6} \frac{log( 1.20)^2}{ ( 0.200)^3}

Ecell = 0.577 V

Read more about Temperature

brainly.com/question/13439286

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