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Airida [17]
3 years ago
8

_KOH+_H3PO4=_K3PO4+_H2O

Chemistry
1 answer:
Evgen [1.6K]3 years ago
4 0

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The balanced chemical equation for given reaction is ~

  • \sf{3KOH + H_3PO_4  \rightarrow K_3PO_4 + 3H_2O}
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Perform the following conversions:
spayn [35]

0 K in Celsius scale is -273 degree Celsius and in Fahrenheit scale 459 degree F.

The degree of a body's heat or cold is referred to as the gas's temperature. It is stated in temperature units such as, degree Celsius, Fahrenheit  and Kelvin these temperature units are interchangeable. To convert Celsius to Fahrenheit ° F = 9/5 ( ° C) + 32, kelvin to Fahrenheit= ° F = 9/5 (K - 273) + 32, Celsius to kelvin K = ° C + 273.  to convert Fahrenheit to Celsius ° C = 5/9 (° F - 32)  In this question,  to convert Fahrenheit to Celsius ° C = 5/9 (° F - 32) = 0-273 K (5/9 - F-32) =459 degree F. and kelvin to Celsius K - 273 = C = -273 degree Celsius

At 8^0C K= 8 + 273 =281 degree Celsius and at 8F , 8= 9/5(k-273) +32 =453 F

To learn more about Fahrenheit and Celsius:

brainly.com/question/1844449

#SPJ4

5 0
2 years ago
Answer this question fast please!
MrRissso [65]

Answer:

A is a physical change, no atoms are being lost its still in it original form

B is a chemical change, it is losing atoms and changing into a new substance

Explanation:

5 0
3 years ago
How do nuclear power plants provide energy?
Troyanec [42]
A process called fission which generates heat to produce steam, which is used by a turbine generator to generate electricity.
3 0
4 years ago
How many grams of calcium carbonate were used if you drew the periodic table on the sidewalk using
german

Based on the data provided, there are 25 g of calcium carbonate in 1.505 × 10^23 atoms.

<h3>What is the moles of calcium carbonate in 1.505 × 10^23 atoms of calcium carbonate?</h3>

The mole of a substance can be calculated as follows:

  • Moles of substance = number of particles/6.02 × 10^23

Moles of calcium carbonate = 1.505 × 10^23/6.02 × 10^23

Moles of calcium carbonate = 0.25 moles

The mass of calcium carbonate in 0.25 moles is calculated as follows:

  • mass = moles × molar mass

molar mass of a calcium carbonate = 100 g/mol

mass of calcium carbonate = 0.25 × 100 = 25 g.

Therefore, there are 25 g of calcium carbonate in 1.505 × 10^23 atoms.

Learn more about molar mass and mass at: brainly.com/question/15476873

8 0
2 years ago
NEED HELP ASAP
Fantom [35]

Answer:

D. potential

Explanation:

D. potential

5 0
2 years ago
Read 2 more answers
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