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LekaFEV [45]
3 years ago
12

Is Y=x-3 and x-y=8 parallel perpendicular or neither

Mathematics
1 answer:
Vinvika [58]3 years ago
6 0
The two lines are parallel
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The scott family wants to fill up their swimming pool to the very top with water.The length of the pool is 50 meters annd the wi
inn [45]

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12,500 meters cubed

Step-by-step explanation:

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4 years ago
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Can somebody prove this mathmatical induction?
Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

\sum \limits_{j=1}^k2^j=2(2^k-1)

3 step:

Check for n=k+1 whether the statement

\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)

is true.

Start with the left side:

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)

According to the 2nd step,

\sum \limits_{j=1}^k2^j=2(2^k-1)

Substitute it into the \ast

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)

So, you have proved the initial statement

4 0
4 years ago
Arrange the events in Polish history in chronological order using the numbers 1-6.
Basile [38]

Answer:

3

5

1

2

4

6

Yan po para sa akin.

4 0
3 years ago
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Find three pairs of equivalent fractions
Mrrafil [7]
1/3 : 2/6
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15/31 : 45/93

hope this helps (;
7 0
3 years ago
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In the first week students at RSM solved 25 percent of their monthly quota of problems. In the second week, they solved 110 perc
natka813 [3]

Answer:

The number of problems solved = 2000

Step-by-step explanation:

Let us assume the monthly quota of problems be x

number of problem solved in first week = 25 % of x =0.25x

number of problems solved in 2nd week = 110% of (problems solved in 1st       week)

                                                         = 1.10 (0.25x)

                                                         =0.275x

number of problem solved 3rd week= 60% of ( problems solved in 1st and 2nd week)

                                                            = 0.60(0.25x+0.275x)

                                                            =0.60(0.525x)

                                                            =0.315x

number of problem solved in 4th week = 320

now we have

number of problems solved in ll 4 weeks = x

0.25x +0.275x+0.315x+320=x

0.84x+320=x

320=x-0.84x

320=0.16 x

x=\frac{320}{0.16}

x=2000

Hence the number of problems solved = 2000



7 0
4 years ago
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