11. Which compound is the most soluble at 10°C? a. Ce2(S04)3 b. NaCl c. KCI d. KCIO3

Which gas law describes the relationship between temperature and pressure at a constant volume

Lelechka [254]

Gay-Lussac's Law: The Pressure Temperature Law

7 0

4 years ago

awhite billiard ball with mass mw = 1.47 kg is moving directly to the right with a speed of v = 3.01 m/s and collides elasticall

pochemuha

Answer:

speed of white ball is 1.13 m/s and speed of black ball is 2.78 m/s

initial kinetic energy = final kinetic energy

$KE = 6.66 J$

Explanation:

Since there is no external force on the system of two balls so here total momentum of two balls initially must be equal to the total momentum of two balls after collision

So we will have

momentum conservation along x direction

$m_1v_{1i} + m_2v_{2i} = m_1v_{1x} + m_2v_{2x}$

now plug in all values in it

$1.47 \times 3.01 + 0 = 1.47 v_1cos68 + 1.47 v_2cos22$

so we have

$3.01 = 0.375v_1 + 0.927v_2$

similarly in Y direction we have

$m_1v_{1i} + m_2v_{2i} = m_1v_{1y} + m_2v_{2y}$

now plug in all values in it

$0 + 0 = 1.47 v_1sin68 - 1.47 v_2sin22$

so we have

$0 = 0.927v_1 - 0.375v_2$

$v_2 = 2.47 v_1$

now from 1st equation we have

$3.01 = 0.375 v_1 + 0.927(2.47 v_1)$

$v_1 = 1.13 m/s$

$v_2 = 2.78 m/s$

so speed of white ball is 1.13 m/s and speed of black ball is 2.78 m/s

Also we know that since this is an elastic collision so here kinetic energy is always conserved to

initial kinetic energy = final kinetic energy

$KE = \frac{1}{2}(1.47)(3.01^2)$

$KE = 6.66 J$

5 0

4 years ago

PLease Help !!! A.S.A.P!!! will be marked as brainlest !!!!! 16 points

White raven [17]

This one is correct

Jamie is correct, because the mechanical energy is converting to electrical energy.

3 0

3 years ago

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Two rods, one made of brass and the other made of copper, are joined end to end. The length of the brass section is 0.300 mm and

Marta_Voda [28]

Answer:

(a) T =45.9°C

(b) m = 124kg

Explanation:

In this problem there I'd heat flowing through bars of different composition.

The current flowing through the two bars mus be the same.

The full solution can be found in the attachment below.

8 0

3 years ago

You have a device that needs a voltage reference of 3.0 V, but you have only a 9.0 V battery. Fortunately, you also have several

Nimfa-mama [501]

Answer:

Explanation:

Solution:

- We are to develop a circuit that has an input of available battery 9.0 V and has an output potential difference of 3.0 V

- We are given:

Battery ..... 9.0 V

Resistors ... 10 Kohms

- We will develop a potential divider circuit by placing a few resistors in series and then connecting in between resistors to get our desired voltage.

- How many resistors should we use ?

We know that if we add series resistance in a circuit the current decreases proportionally. However, the potential difference across resistors also changes.

- Our desired voltage is a ratio of input battery voltage.

Input / Output = 9 / 3 = 3

We can use this ratio as the number of "Identical resistors" that can be placed in series to give us the desired voltage. Note: This would not be true if we did not had any identical resistors.

- We will place 3, 10 Kohms resistors in series.

- To verify we will calculate the potential difference across each resistor. The current of the total circuit is:

I = V / R_eq

R_eq = 3*R = 30 kohms

I = 9 / 30,000 = 0.0003 Amps

- Now the potential difference for each resistor:

V = I*R_each

V = 0.0003*(10,000)

V = 3.0 V

- We can take two leads across any 10 kohms resistor and the potential difference across the leads would be the desired voltage 3.0 V.

8 0

3 years ago

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