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forsale [732]
3 years ago
6

not all objects have a volume that is measured easily. If you were to determine the mass, volume, and density of your textbook,

a container of milk, and an air-filled balloon, how would you do it
Physics
2 answers:
Maru [420]3 years ago
8 0

Answer:

Explanation:

Volume is defined as the space occupied by any object. As there are three forms of substance found in nature which is solid, liquid and gas , different methods are used to calculate there volumes.

Mass can be calculated by using various measuring tools. For volume we need different techniques as each object has different nature.

1: Volume of book - As a book is in shape of a cuboid, we can measure the length, breath and height of the book. As volume of cuboid is equal to the product of these three values, we will get the volume of book.

2: Volume of a container of milk : Try to pour the milk into any container that has a specific shape and is filled up to the rim. In this vase the volume of the container will be the volume of milk.

3 : Volume of air - filled balloon : As we know density of air is 28.97 kg/m^3, we can simply divide the mass of air balloon with the density.

Density of book and milk can be calculated by dividing mass of these objects with there respective volume.

Maslowich3 years ago
3 0

Text book: We can measure the mass of the text book easily by weighing machine, to measure the volume we need to measure the length, width, and height of the text book by the ruler, by multiplying these dimension we can get the volume of the text book, and by dividing the mass of the book with its volume we can get the density of the book.

Milk Container: We can measure the mass of the milk container easily by weighing machine, now (assuming the milk container is cylindrical in shape) we need to measure its height, and and diameter and by the formula (π*r^2*h) we can measure its volume, and and by dividing the mass  with its volume we can get the density of the milk container.

Air filled balloon: we can measure the mass of the air filled balloon by weighing it weight machine, we know that the density of air is 28.97 kg/m^3, by dividing the mass of the balloon with the denisty of air we can get the volume of the balloon.

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El coeficiente de variación de la resistencia con la temperatura del carbón es -0.0005/°c.Si la resistencia de una resistencia d
Doss [256]

Answer:

 R (120) = 940Ω

Explanation:

The variation in resistance with temperature is linear in metals

           ΔR (T) = R₀ α ΔT

where α is the coefficient of variation of resistance with temperature, in this case α = -0,0005 / ºC

let's calculate

            ΔR = 1000 (-0,0005) (120-0)

            ΔR = -60 Ω

            ΔR = R (120) + R (0) = -60

            R (120) = -60 + R (0)

            R (120) = -60 + 1000

            R (120) = 940Ω

3 0
3 years ago
A certain metal wire has a cross sectional area of 1 mm2 and is 1 m long. when it is hung from the ceiling and a 10 kg mass is h
kvasek [131]
From the Hooke's law , the extension force of an elastic material is directly proportional to the extension. 
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 F = 10 × 10 = 100 N
e = 1mm or 0.001 m
Hence, k = F/e
                = 100 N/ 0.001
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A 250 N force pulls on a box horizontally to the right. The box is moving at constant speed.
lana66690 [7]

Answer:

its 34

Explanation:

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A grape is thrown straight up in the air. If it was thrown at 2 m/s, how high will it go in the air?
ser-zykov [4K]

Answer:

Answer: <u>Height</u><u> </u><u>is</u><u> </u><u>0</u><u>.</u><u>2</u><u>0</u><u>4</u><u> </u><u>m</u>

Explanation:

At the highest point, it is called the maximum height.

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{ \rm{ {v}^{2}  =  {u}^{2}  + 2gs}}

• At maximum height, v is zero

• u is initial speed

• g is -9.8 m/s²

• s is the height

{ \rm{0 {}^{2}  =  {2}^{2}   -  (2 \times 9.8 \times s)}} \\  \\ { \rm{4 = 19.6s}} \\  \\ { \rm{s = 0.204 \: m}}

4 0
2 years ago
Read 2 more answers
A short current element dl⃗ = (0.500 mm)j^ carries a current of 5.40 A in the same direction as dl⃗ . Point P is located at r⃗ =
SashulF [63]

Answer:

The magnetic field along x axis is

B_{x}=1.670\times10^{-10}\ T

The magnetic field along y axis is zero.

The magnetic field along z axis is

B_{z}=3.484\times10^{-10}\ T

Explanation:

Given that,

Length of the current element dl=(0.5\times10^{-3})j

Current in y direction = 5.40 A

Point P located at \vec{r}=(-0.730)i+(0.390)k

The distance is

|\vec{r}|=\sqrt{(0.730)^2+(0.390)^2}

|\vec{r}|=0.827\ m

We need to calculate the magnetic field

Using Biot-savart law

B=\dfrac{\mu_{0}}{4\pi}\timesI\times\dfrac{\vec{dl}\times\vec{r}}{|\vec{r}|^3}

Put the value into the formula

B=10^{-7}\times5.40\times\dfrac{(0.5\times10^{-3})\times(-0.730)i+(0.390)k}{(0.827)^3}

We need to calculate the value of \vec{dl}\times\vec{r}

\vec{dl}\times\vec{r}=(0.5\times10^{-3})\times(-0.730)i+(0.390)k

\vec{dl}\times\vec{r}=i(0.350\times0.5\times10^{-3}-0)+k(0+0.730\times0.5\times10^{-3})

\vec{dl}\times\vec{r}=0.000175i+0.000365k

Put the value into the formula of magnetic field

B=10^{-7}\times5.40\times\dfrac{(0.000175i+0.000365k)}{(0.827)^3}

B=1.670\times10^{-10}i+3.484\times10^{-10}k

Hence, The magnetic field along x axis is

B_{x}=1.670\times10^{-10}\ T

The magnetic field along y axis is zero.

The magnetic field along z axis is

B_{z}=3.484\times10^{-10}\ T

7 0
3 years ago
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