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forsale [732]
3 years ago
6

not all objects have a volume that is measured easily. If you were to determine the mass, volume, and density of your textbook,

a container of milk, and an air-filled balloon, how would you do it
Physics
2 answers:
Maru [420]3 years ago
8 0

Answer:

Explanation:

Volume is defined as the space occupied by any object. As there are three forms of substance found in nature which is solid, liquid and gas , different methods are used to calculate there volumes.

Mass can be calculated by using various measuring tools. For volume we need different techniques as each object has different nature.

1: Volume of book - As a book is in shape of a cuboid, we can measure the length, breath and height of the book. As volume of cuboid is equal to the product of these three values, we will get the volume of book.

2: Volume of a container of milk : Try to pour the milk into any container that has a specific shape and is filled up to the rim. In this vase the volume of the container will be the volume of milk.

3 : Volume of air - filled balloon : As we know density of air is 28.97 kg/m^3, we can simply divide the mass of air balloon with the density.

Density of book and milk can be calculated by dividing mass of these objects with there respective volume.

Maslowich3 years ago
3 0

Text book: We can measure the mass of the text book easily by weighing machine, to measure the volume we need to measure the length, width, and height of the text book by the ruler, by multiplying these dimension we can get the volume of the text book, and by dividing the mass of the book with its volume we can get the density of the book.

Milk Container: We can measure the mass of the milk container easily by weighing machine, now (assuming the milk container is cylindrical in shape) we need to measure its height, and and diameter and by the formula (π*r^2*h) we can measure its volume, and and by dividing the mass  with its volume we can get the density of the milk container.

Air filled balloon: we can measure the mass of the air filled balloon by weighing it weight machine, we know that the density of air is 28.97 kg/m^3, by dividing the mass of the balloon with the denisty of air we can get the volume of the balloon.

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A lightning strike can transfer as much as electrons from the cloud to the ground. if the strike lasts 2ms , what is the average
malfutka [58]

The average electric current in the lightning will be 8 × 10^{-17} A

<h3>Why Lightning Conductors on top of a tower ?</h3>

The lightning conductors are long metal strips running from the spike end of a conductor on the top of a building to the earth. They are used to prevent buildings from destruction when struck by thunder or lightning.

Given that a lightning strike can transfer as much as electrons from the cloud to the ground. if the strike lasts 2ms, to calculate the average electric current in the lightning, we will first consider the charge released.

one charge = 1.6 × 10^{-19} C

Average current I = Q/t

Where

  • Q = charge = 1.6 × 10^{-19} C
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  • I = current = ?

Substitute all the parameters into the formula

I = 1.6 × 10^{-19} C ÷ 2 × 10^{-3}

I = 8 × 10^{-17} A

Therefore, the average electric current in the lightning will be 8 × 10^{-17} A

Learn more about Lightning here: brainly.com/question/3183045

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