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forsale [732]
3 years ago
6

not all objects have a volume that is measured easily. If you were to determine the mass, volume, and density of your textbook,

a container of milk, and an air-filled balloon, how would you do it
Physics
2 answers:
Maru [420]3 years ago
8 0

Answer:

Explanation:

Volume is defined as the space occupied by any object. As there are three forms of substance found in nature which is solid, liquid and gas , different methods are used to calculate there volumes.

Mass can be calculated by using various measuring tools. For volume we need different techniques as each object has different nature.

1: Volume of book - As a book is in shape of a cuboid, we can measure the length, breath and height of the book. As volume of cuboid is equal to the product of these three values, we will get the volume of book.

2: Volume of a container of milk : Try to pour the milk into any container that has a specific shape and is filled up to the rim. In this vase the volume of the container will be the volume of milk.

3 : Volume of air - filled balloon : As we know density of air is 28.97 kg/m^3, we can simply divide the mass of air balloon with the density.

Density of book and milk can be calculated by dividing mass of these objects with there respective volume.

Maslowich3 years ago
3 0

Text book: We can measure the mass of the text book easily by weighing machine, to measure the volume we need to measure the length, width, and height of the text book by the ruler, by multiplying these dimension we can get the volume of the text book, and by dividing the mass of the book with its volume we can get the density of the book.

Milk Container: We can measure the mass of the milk container easily by weighing machine, now (assuming the milk container is cylindrical in shape) we need to measure its height, and and diameter and by the formula (π*r^2*h) we can measure its volume, and and by dividing the mass  with its volume we can get the density of the milk container.

Air filled balloon: we can measure the mass of the air filled balloon by weighing it weight machine, we know that the density of air is 28.97 kg/m^3, by dividing the mass of the balloon with the denisty of air we can get the volume of the balloon.

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Katena32 [7]

Answer:

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8 0
2 years ago
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20. Using the picture, how many neutrons does lithium have?
Igoryamba

Answer:

No. of Neutrons = 3

Explanation:

The atomic number of Lithium is given as 3 in the symbol while the mass number is given as 5.941 which is approximately equal to 6.

Mass Number = No. of Protons + No. of Neutrons = 6

Atomic Number = Number of Electrons = No. of Protons = 3

Therefore,

Mass Number - Atomic Number = (No. of Protons + No. of Neutrons) - No. of Protons

Mass Number - Atomic Number = No. of Neutrons

No. of Neutrons = 6 - 3

<u>No. of Neutrons = 3 </u>

8 0
3 years ago
PLEASE ANSWER, HURRY! THANKS :) A green object will absorb ____________________ light and reflect ____________________ light. Ex
olga55 [171]

Answer:

It will absorb yellow and reflect green

8 0
3 years ago
The objective lens of a microscope has a focal length of 5.5mm. Part A What eyepiece focal length will give the microscope an ov
son4ous [18]

Complete Question

The distance between the objective and eyepiece lenses in a microscope is 19 cm . The objective lens has a focal length of 5.5 mm .

What eyepiece focal length will give the microscope an overall angular magnification of 300?

Answer:

The  eyepiece focal length is  f_e  = 0.027 \ m

Explanation:

From the question we are told that

    The focal length is  f_o =  5.5 \ mm =  -0.0055 \ m

This negative sign shows the the microscope is diverging light

     The  angular magnification is m = 300

     The  distance between the objective and the eyepieces lenses is  Z =  19 \ cm  = 0.19 \ m

Generally the magnification is mathematically represented as

        m  =  [\frac{Z - f_e }{f_e}] [\frac{0.25}{f_0} ]

Where f_e is the eyepiece focal length of the microscope

  Now  making f_e the subject  of the formula

         f_e  = \frac{Z}{1 - [\frac{M  *  f_o }{0.25}] }

substituting values

        f_e  = \frac{ 0.19 }{1 - [\frac{300  *  -0.0055 }{0.25}] }

         f_e  = 0.027 \ m

     

5 0
2 years ago
A 4-kg object falls vertically a distance of 5 m. its potential energy has changed by approximately how much?
Brums [2.3K]
Given:
m = 4 kg, the mass of the object
h = 5 m, distance fallen

Neglect air resistance.

The PE (potential energy) is 
PE = mgh = (4 kg)*(9.8 m/s²)*(5 m) = 196 J

The PE is converted into KE (kinetic energy) after the fall. 
Therefore the PE decreased by 196 J ≈ 200 J

Answer: d. It has decreased by 200 J
7 0
3 years ago
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