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FrozenT [24]
2 years ago
13

The function f(x) is an increasing function about which little else is known about other than f(2)=7 and f'(2)=5. Find (f^-1)'(7

).
Mathematics
1 answer:
andreyandreev [35.5K]2 years ago
3 0

Since f(x) is (strictly) increasing, we know that it is one-to-one and has an inverse f^(-1)(x). Then we can apply the inverse function theorem. Suppose f(a) = b and a = f^(-1)(b). By definition of inverse function, we have

f^(-1)(f(x)) = x

Differentiating with the chain rule gives

(f^(-1))'(f(x)) f'(x) = 1

so that

(f^(-1))'(f(x)) = 1/f'(x)

Let x = a; then

(f^(-1))'(f(a)) = 1/f'(a)

(f^(-1))'(b) = 1/f'(a)

In particular, we take a = 2 and b = 7; then

(f^(-1))'(7) = 1/f'(2) = 1/5

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we can have a triangle  and we know that there are two angles. 

30º and a 45º + 105 =180º angle. applying the sides. 

therefore if we have the whole triangle completed we have a constant triangle. 


so it tell us we can you’se SOH CAH TOA 

we can varrify what kind of triangle we are using. 


for example if we were to use  Sin I would do 


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if you would want to solve for  sin 30/2 and sin 105, then we solve. 

 

or Sin 30/2  and Sin 105 as well. 


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