Ask question

Ask question

All categories

3 years ago

15

A ball is thrown horizontally from the top of a tower at 30m high, and lands 15m from its base. What is the ball's initial speed

?

1 answer:

PilotLPTM [1.2K]3 years ago

5 0

Answer:

This question requires gravitational acceleration,t=（2h/g）^ 1/2,Level the initial speed is 15/t.

You might be interested in

As the launch force increase the launch velocity will

FrozenT [24]

Answer:

As the launch force increase the launch velocity will

<em><u>Increase</u></em>

The reason for your answer to number six is because

<em><u>There is a direct relationship between force and acceleration.</u></em>

<em><u /></em>

Explanation:

<em>It is known all over the place that, there is a direct relationship between Force and acceleration of an object leading to an increase in force being directly proportional to the increase in the acceleration of the given object and vice versa.</em>

5 0

3 years ago

¿Un cuerpo que se encuentra a 5°C puede darle calor a otro cuerpo?

likoan [24]

I uploaded the answer to a file hosting. Here's link:

tinyurl.com/wpazsebu

7 0

3 years ago

A person's temperature is 40

nekit [7.7K]

It would be: 40 + 272 = 313 K

In short, Your Answer would be Option A

Hope this helps!

4 0

3 years ago

A car with a velocity of 22 m/s is accelerated at a rate of 1.6m/s2 for 6.8s. determine the final velocity

Ivahew [28]

A car with a velocity of 22 m/s is accelerated at a rate of 1.6 $m/s^2$ for 6.8s has the final velocity t be 32.88 m/s.

The acceleration means the amount of velocity changing per unit time.

The given data:

initial velocity, u = 22 m/s

time, t = 6.8 s

acceleration, a = 1.6 $m/s^2$

We will be using the equation of motion:

v = u + at

$\therefore v=22+1.(6.8)$

$\Rightarrow v=22+10.88$

$\Rightarrow v=32.88 \ m/s$

The final velocity become 32.88 m/s.

To learn more about Attention here:

https://brainly.in/question/10557838

#SPJ4

3 0

2 years ago

A 120 V fish-tank heater is rated at 130W. Calculate (a) the current through the heater when it is operating, and (b) its resist

7nadin3 [17]

Explanation:

The power P dissipated by a heater is defined as

$P = VI$

where V is the voltage and I is the current.

a) The current running through a 130-W heater is

$I = \dfrac{P}{V} = \dfrac{130\:\text{W}}{120\:\text{V}} = 1.08\:\text{A}$

b) The resistance <em>R</em><em> </em>of the heater is

$P = VI = (IR)I = I^2R$

where $V= IR$ is our familiar Ohm's Law.

$\Rightarrow R = \dfrac{P}{I^2} = \dfrac{130\:\text{W}}{(1.08\:\text{A})^2}$

$R = 110.8\:Ω$

8 0

3 years ago