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velikii [3]
2 years ago
11

A 1994 Ford Mustang is driving down a road with a constant speed of 30 31/5, The engine must

Physics
1 answer:
coldgirl [10]2 years ago
4 0

The power rating of the engine is 150000 W.

<h3>What is power?</h3>

Power can be defined as the rate at which energy is used or consumed by a body.

To calculate the power of the engine, we use the formula below.

Formula:

  • P = FV............. Equation 1

Where:

  • P = Power of rating of the engine
  • F = Force of the engine
  • V = Velocity of the engine.

From the question,

Given:

  • F = 5000 N
  • V = 30 m/s.

Substitute these values into equation 1

  • P = 5000×30
  • P = 150000 W.

Hence, The power rating of the engine is 150000 W.

Learn more about power here: brainly.com/question/1173325



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When two atoms of the same nonmetal react, they often form a(an) A. ionic bond. B. polyatomic ion. C. diatomic molecule. D. pola
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What is the advantage of a free market economy??
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A free market economy<span> has two key </span>advantages<span>. First, it allows for individuals to innovate. Individuals have the freedom to create new ideas, new products, and new services to sell for profit. They are not required to only produce what the government tells them to produce.</span>
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3 years ago
A proton, starting from rest, accelerates through a potential difference of 1.0 kV and then moves into a magnetic field of 0.040
Minchanka [31]

Answer:

r = 0.11 m

Explanation:

The radius of the proton's resulting orbit can be calculated equaling the force centripetal (Fc) with the Lorentz force (F_{B}), as follows:

F_{c} = F_{B} \rightarrow \frac{m*v^{2}}{r} = qvB (1)

<u>Where:</u>

<em>m: is the proton's mass =  1.67*10⁻²⁷ kg</em>

<em>v: is the proton's velocity</em>

<em>r: is the radius of the proton's orbit</em>

<em>q: is the proton charge = 1.6*10⁻¹⁹ C</em>

<em>B: is the magnetic field = 0.040 T </em>

Solving equation (1) for r, we have:

r = \frac{mv}{qB}   (2)

By conservation of energy, we can find the velocity of the proton:

K = U \rightarrow \frac{1}{2}mv^{2} = q*\Delta V   (3)

<u>Where:</u>

<em>K: is kinetic energy</em>

<em>U: is electrostatic potential energy</em>

<em>ΔV: is the potential difference = 1.0 kV </em>

Solving equation (3) for v, we have:

v = \sqrt{\frac{2q\Dela V}{m}} = \sqrt{\frac{2*1.6 \cdot 10^{-19} C*1.0 \cdot 10^{3} V}{1.67 \cdot 10^{-27} kg}} = 4.38 \cdot 10^{5} m/s  

Now, by introducing v into equation (2), we can find the radius of the proton's resulting orbit:

r = \frac{mv}{qB} = \frac{1.67 \cdot 10^{-27} kg*4.38 \cdot 10^{5} m/s}{1.6 \cdot 10^{-19} C*0.040 T} = 0.11 m

Therefore, the radius of the proton's resulting orbit is 0.11 m.

I hope it helps you!  

5 0
3 years ago
Calculate the displacement of an object at 2.0 seconds when thrown straight up with an
Licemer1 [7]

Answer:

<h3>30m</h3>

Explanation:

Velocity is the change of rate of displacement with respect to time.

velocity = displacement/time

Given

initial velocity = 15 m/s.

time taken =2 secs

Required

Displacement of the object

From the formula;

Displacement = Velocity * time

Displacement = 15 * 2

Displacement = 30m

<em>Hence the displacement of the object is 30m</em>

8 0
3 years ago
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