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velikii [3]
2 years ago
11

A 1994 Ford Mustang is driving down a road with a constant speed of 30 31/5, The engine must

Physics
1 answer:
coldgirl [10]2 years ago
4 0

The power rating of the engine is 150000 W.

<h3>What is power?</h3>

Power can be defined as the rate at which energy is used or consumed by a body.

To calculate the power of the engine, we use the formula below.

Formula:

  • P = FV............. Equation 1

Where:

  • P = Power of rating of the engine
  • F = Force of the engine
  • V = Velocity of the engine.

From the question,

Given:

  • F = 5000 N
  • V = 30 m/s.

Substitute these values into equation 1

  • P = 5000×30
  • P = 150000 W.

Hence, The power rating of the engine is 150000 W.

Learn more about power here: brainly.com/question/1173325



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Ilia_Sergeevich [38]

True. It would be false if the statement was "trunk rotation is the most common <em>static</em> flexibility assessment."


So, you're answer should be "true". Hope that helped!

6 0
4 years ago
Thermodynamics
Akimi4 [234]

Answer:

E = 3.8 kJ

Explanation:

Given that,

The mass of the object, m = 10 g = 0.01 kg

The heat of fusion of  aluminum is 380 kJ/kg

We need to find the energy required to melt the mass of the aluminium. It can be calculated as follows:

E = mL

So,

E = 0.01 × 380

E = 3.8 kJ

So, the energy required to melt the mass is equal 3.8 kJ.

7 0
3 years ago
A student starts a food fight by throwing a 0.5 kg burrito at some girl he likes. He throws it kind-of hard so he accelerates it
Elenna [48]

Explanation:

m = mass of burrito thrown by the student = 0.5 kg

a = acceleration of the burrito thrown by the student = 3 m/s²

F = force applied by the student on the burrito = ?

According to newton's second law , the net force on an object is the product of its mass and acceleration. it is given as

F = ma

inserting the values

F = (0.5) (3)

F = 1.5 N

hence the net force on the burrito comes out to be 1.5 N

4 0
3 years ago
Each plate of a parallel‑plate capacitor is a square of side 3.63 cm, and the plates are separated by 0.473 mm. The capacitor is
NARA [144]

Answer:

E= 55.53 x 10³ V/m

Explanation:

Given that

a=  3.63 cm

Area ,A= a²

distance ,d= 0.473 mm

Stored energy ,U = 8.49 nJ

Value of capacitor given as

C=\dfrac{\varepsilon _oA}{d}

By putting the values

C=\dfrac{8.85\times 10^{-12}\times 3.63^2\times 10^{-4}}{0.473\times 10^{-3}}

C=2.46 x 10⁻¹¹ F

U=\dfrac{1}{2}CV^2

V=Voltage difference

V=\sqrt{\dfrac{2U}{C}}

V=\sqrt{\dfrac{2\times 8.49\times 10^{-9}}{2.46\times 10^{-11}}}

V=26.27 V

V= E d

E=Electric filed

26.27 = E x 0.473 x 10⁻³

E= 55.53 x 10³ V/m

7 0
4 years ago
PLEASE HELP 15 POINTS!!!!
goldfiish [28.3K]

Answer:

15 degrees Celsius

Explanation:

8 0
3 years ago
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