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2 years ago

A 1994 Ford Mustang is driving down a road with a constant speed of 30 31/5, The engine must

Physics

1 answer:

coldgirl [10]2 years ago

4 0

The power rating of the engine is 150000 W.

<h3>What is power?</h3>

Power can be defined as the rate at which energy is used or consumed by a body.

To calculate the power of the engine, we use the formula below.

Formula:

P = FV............. Equation 1

Where:

P = Power of rating of the engine
F = Force of the engine
V = Velocity of the engine.

From the question,

Given:

F = 5000 N
V = 30 m/s.

Substitute these values into equation 1

P = 5000×30
P = 150000 W.

Hence, The power rating of the engine is 150000 W.

Learn more about power here: brainly.com/question/1173325

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When two atoms of the same nonmetal react, they often form a(an) A. ionic bond. B. polyatomic ion. C. diatomic molecule. D. pola

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What is the advantage of a free market economy??

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3 years ago

A proton, starting from rest, accelerates through a potential difference of 1.0 kV and then moves into a magnetic field of 0.040

Minchanka [31]

Answer:

r = 0.11 m

Explanation:

The radius of the proton's resulting orbit can be calculated equaling the force centripetal (Fc) with the Lorentz force ( $F_{B}$ ), as follows:

$F_{c} = F_{B} \rightarrow \frac{m*v^{2}}{r} = qvB$ (1)

Where:

m: is the proton's mass = 1.67*10⁻²⁷ kg

v: is the proton's velocity

r: is the radius of the proton's orbit

q: is the proton charge = 1.6*10⁻¹⁹ C

B: is the magnetic field = 0.040 T

Solving equation (1) for r, we have:

$r = \frac{mv}{qB}$ (2)

By conservation of energy, we can find the velocity of the proton:

$K = U \rightarrow \frac{1}{2}mv^{2} = q*\Delta V$ (3)

Where:

K: is kinetic energy

U: is electrostatic potential energy

ΔV: is the potential difference = 1.0 kV

Solving equation (3) for v, we have:

$v = \sqrt{\frac{2q\Dela V}{m}} = \sqrt{\frac{2*1.6 \cdot 10^{-19} C*1.0 \cdot 10^{3} V}{1.67 \cdot 10^{-27} kg}} = 4.38 \cdot 10^{5} m/s$

Now, by introducing v into equation (2), we can find the radius of the proton's resulting orbit:

$r = \frac{mv}{qB} = \frac{1.67 \cdot 10^{-27} kg*4.38 \cdot 10^{5} m/s}{1.6 \cdot 10^{-19} C*0.040 T} = 0.11 m$

Therefore, the radius of the proton's resulting orbit is 0.11 m.

I hope it helps you!

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3 years ago

Calculate the displacement of an object at 2.0 seconds when thrown straight up with an

Licemer1 [7]

Answer:

Explanation:

Velocity is the change of rate of displacement with respect to time.

velocity = displacement/time

Given

initial velocity = 15 m/s.

time taken =2 secs

Required

Displacement of the object

From the formula;

Displacement = Velocity * time

Displacement = 15 * 2

Displacement = 30m

Hence the displacement of the object is 30m

8 0

3 years ago