All categories

2 years ago

What's a good way to start the problem?

1 answer:

5 0

Answer: Start by writing down the problem in your own words using as much detail as possible. Be as specific as possible in your description.

Explanation:

You might be interested in

Use the image below to answer the following question (ruler not to scale).

Svetradugi [14.3K]

Answer:

it depends on wether the + and - are facing eachother

or away from eachother

Explanation:

4 0

2 years ago

Read 2 more answers

Tangential velocity 2. Parabolic pathway 3. Projectile 4. Centripetal acceleration 5. Centripetal force a. acceleration towards

Stels [109]

1. Tangential velocity:

e) the instantaneous velocity of a body moving in a circular path.

2. Parabolic pathway

c. a curved path followed by projectiles

3. Projectile

d) an object projected through space, traveling in two dimensions, that accelerates vertically due to gravity.

4. Centripetal acceleration

a) acceleration towards the center caused by the centripetal force

5. Centripetal force

b) a force which keeps a body moving with a uniform speed along a circular path and is directed along the radius towards the center

4 0

3 years ago

If the system is operated on mars, through what distance would the 18.0-kg mass have to fall to give the same amount of kinetic

-Dominant- [34]

The previous part of the exercise says:
"Engineers are designing a system by which a falling mass m imparts kinetic energy to a rotating uniform drum to which it is attached by thin, very light wire wrapped around the rim of the drum. There is no appreciable friction in the axle of the drum, and everything starts from rest. This system is being tested on Earth, but it is to be used on Mars, where the acceleration due to gravity is 3.71 m/s². In the Earth tests, when m is set to 18.0 kg and allowed to fall through 5.50 m, it gives 300.0 J of kinetic energy to the drum."

Since Kearth = Kmars, we have, for conservation of energy, that also the potential energies must be equal:
Uearth = Umars

which means:
m · gearth · hearth = m · gmars · hmars

we can solve for hmars:
hmars = (gearth / gmars) · hearth
= (9.8 / 3.71) · 5.50
= 14.53m

Therefore, the correct answer will be: the mass would have to fall from an height of 14.53m.

5 0

3 years ago

The Graph above shows the speed of a car traveling in a straight line as a function of time. The car accelerates uniformly and r

devlian [24]

Answer:

Where is the graph??

If a car travels from zero to 4 m/s ins 8 sec

a = 4 / 8 = .5 m/s^2

V (2) = 2 * .5 = 1 m/s after 2 sec

S = V t + 1/2 a t^2

S = 1 * 3.9 + 1/2 * 1/2 *3.9^2 = 3.9 + 3.80 = 7.70 m from 2 to 5.9 sec

Check:

Total distance traveled = 1/2 a t^2 = 5.9^2 / 4 = 8.70 m

Distance traveled in 2 sec = 1/2 * 1/2 * 4 = 1 m

Total distance from 2 to 5.9 = 8.7 - 1 = 7.7 m agreeing with thw above

3 0

2 years ago

How much power does the athlete produce if he has 28,056J of work over 45s?

Jlenok [28]

Explanation:

Power = Work done ÷ Time

P = 28056 ÷ 45 Watt

P = 623.46 Watt

5 0

2 years ago