The kinetic energy J of the eagle is mathematically given as
K.E=1350
<h3>What is the kinetic energy (in joule) of the eagle? </h3>
Question Parameters:
A 12-kilogram eagle is flying at 15 meters/sec.
Generally, the equation for the kinetic energy is mathematically given as
K.E=1/2mv^2
Therefore
K.E=1/2(12)(15)^2
K.E=1350J
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Answer: This is an organic combustion reaction
<span>The three methods are
wet gas desulfurisation(W)
dry gas desulfurisation(D)
seawater gas desulfurisation.(S)
In method W Calcium carbonate, CaCO3 material is used and material is obtained by quarrying. The solid waste is sold for use in buildings.
In method D Calcium oxide, CaO is used and the material is obtained by Thermal decomposition of calcium carbonate. Solid waste is sent to landfill.
In this method material is obtained from sea water. Liquid waste is returned to the sea.</span>
Answer: 1.07×10^-20microlitre
Explanation:
1cm3 = 1000microlitres
1.07×10^-23 cm3 of tungsten = 1.07×10^-23 x 1000 = 1.07×10^-20microlitre
Answer:
Volume occupied by 55.5 moles of water gas at STP = 1240 Liters.
Explanation:
1st keep in mind that 'volume' in the context of problems like this apply only to the gas phase form of the substance. Water in solid form (ice) or liquid form (liquid water) do not apply. Volume in this case is referred to as 'molar volume' and is a gas occupying 22.4 liters at STP conditions (0°C, 1Atm).
So, if 1 molar volume of water gas (steam) occupies 22.4 Liters at STP, then 55.5 moles of water gas occupies 22.4 Liters/mole x 55.5 moles = 1243.2 Liters, or 1240 Liters (3 sig. figs.). :-)