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White raven [17]
3 years ago
9

1-Two metal samples with equal masses are heated by equal amounts of energy. The temperature of Sample A rose 10oC while the tem

perature of Sample B increased by 20oC. What can you determine about the specific heat capacity of these substances?
2-A sample of a metal with a mass of 10.0 g cooled from 50.4 oC to 25.0 oC, releasing of 168 Joules of heat. What is the specific heat of the metal sample?
Chemistry
1 answer:
makkiz [27]3 years ago
8 0

Answer:

the channel tunnel has been a very busy and challenging experience and we are mot doing.

Explanation:

ok and I like the country studies opportunity and I will be found by him too as he is a fact in the sentence.

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The 18o:16o abundance ratio in some meteorites is greater than that used to calculate the average atomic mass of oxygen on earth
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Answer: The average mass of the oxygen atom in these meteorites will be greater than the terrestrial oxygen atom.

Explanation:

Average atomic mass of an element is defined as the summation of the product of the atomic masses and fractional abundances of its isotopes.

Equation to calculate the average atomic mass will be given by:

\text{Average atomic mass}=\sum_{i=1}^n(\text{Atomic mass of an isotopes})_i\times (\text{fractional abundance})_i

We are given that the abundance ratio of the oxygen in meteorites is more than the terrestrial oxygen atom.

As, from the formula, average atomic mass of an element is directly proportional to the fractional abundance of the isotopes. Hence, with increase in the abundance, the average atomic mass also increases.

Therefore, the average mass of the oxygen atom in these meteorites will be greater than the terrestrial oxygen atom.

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Find the initial temperature of 45.0g of water if its final Temperature after submerging a metal with the mass of 8.5g is 22.0°C
Korolek [52]

The initial temperature of the water that resulted in the final temperature of the water-metal mixture is 20.7 ⁰C.

<em>"Your question is not complete, it seems to be missing the following information;"</em>

the specific heat capacity of the metal is 0.45 J/g⁰C.

The given parameters;

  • <em>mass of water, </em>m_w<em> = 45 g</em>
  • <em>final temperature of the water, </em>t_w<em> = 22 ⁰C</em>
  • <em>mass of the metal, m = 8.5 g</em>
  • <em>initial temperature of the metal, t = 82 ⁰C.</em>
  • <em>specific heat capacity of the metal, c = 0.45 J/g⁰C.</em>

The initial temperature of the water will be calculated by applying the principle of conservation of energy;

<em>heat gained by water = heat lost by metal</em>

Q_{water} = Q_{metal}

m_wc_w \Delta t_w = mc\Delta t

where;

c_w <em>is the specific heat capacity of the water = 4.184 J/g⁰C.</em>

<em />

<em>Substitute the given values;</em>

45 x 4.184 x (22 - t) = 8.5 x 0.45 x (85 - 22)

4142.16  - 188.28t = 240.98

188.28t  = 4142.16  - 240.98

188.28t  = 3901.18

t = \frac{3901.18}{188.28} \\\\t = 20.7 \ ^0 C

Thus, the initial temperature of the water that resulted in the final temperature of the water-metal mixture is 20.7 ⁰C.

Learn more here:brainly.com/question/15345295

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