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Vesnalui [34]
3 years ago
14

A chemist makes of nickel(II) chloride working solution by adding distilled water to of a stock solution of nickel(II) chloride

in water.Calculate the concentration of the chemist's working solution. Round your answer to significant digits.
Chemistry
1 answer:
Lady_Fox [76]3 years ago
3 0

Answer:

0.0900 mol/L

Explanation:

<em>A chemist makes 330. mL of nickel(II) chloride working solution by adding distilled water to 220. mL of a 0.135 mol/L stock solution of nickel(II) chloride in water. Calculate the concentration of the chemist's working solution. Round your answer to significant digits.</em>

Step 1: Given data

  • Initial concentration (C₁): 0.135 mol/L
  • Initial volume (V₁): 220. mL
  • Final concentration (C₂): ?
  • Final volume (V₂): 330. mL

Step 2: Calculate the concentration of the final solution

We prepare a dilute solution from a concentrated one. We can calculate the concentration of the working solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁/V₂

C₂ = 0.135 mol/L × 220. mL/330. mL = 0.0900 mol/L

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Anestetic [448]

The mass of plutonium that will remain after 1000 years if the initial amount is 5 g when the half life of plutonium-239 (239pu, pu-239) is 24,100 years is 2.5 g

The equation is Mr=Mi(1/2)^n

where n is the number of half-lives

Mr is the mass remaining after n half lives

Mi is the initial mass of the sample

To find n, the number of half-lives, divide the total time 1000 by the time of the half-life(24,100)

n=1000/24100=0.0414

So Mr=5x(1/2)^1=2.5 g

The mass remaining is 2.5 g

  • The half life is the time in which the concentration of a substance decreases to half of the initial value.

Learn more about half life at:

brainly.com/question/24710827

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8 0
1 year ago
Calculate OH- given H3 O+ = 1.40 *10^-4 M
vova2212 [387]

3.16 X 10^-11 M is the [OH-] concentration when H3O+ = 1.40 *10^-4 M.

Explanation:

data given:

H30+= 1.40 X 10^-4 M\

Henderson Hasslebalch equation to calculate pH=

pH = -log10(H30+)

putting the values in the equation:

pH = -log 10(1.40 X 10^-4 M)

pH = 3.85

pH + pOH =14

pOH = 14 - 3.85

pOH = 10.15

The OH- concentration from the pOH by the equation:

pOH = -log10[OH-]

10.5= -log10[OH-]

[OH-] = 10^-10.5

[OH-]  = 3.16 X 10^-11 is the concentration of OH ions when hydronium ion concentration is 1.40 *10^-4 M.

8 0
3 years ago
How many independent variables can you have in an experiment for it to be valid?
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Answer:

There are often not more than one or two independent variables tested in an experiment.

3 0
3 years ago
The balanced chemical equation for the reaction between PCl5 and water is given below. If 3.45 moles of HCl are produced, how ma
enyata [817]
The coefficients of the substances give you the ratio of the number of moles.
The 4 before the H2O and the 5 before the HCl tell you that for every 5 moles of HCl created, 4 moles of H2O had to react.

Therefore:
(3.45mol HCl)(\frac{4 mol H2O}{5 mol HCl})
can be used to find the moles of H2O that react.

(3.45mol HCl)(\frac{4 mol H2O}{5 mol HCl}) = 2.76 mol H20
6 0
3 years ago
Write the chemical symbols for three different atoms or atomic cations with 12 electrons.
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2) Atomic number of aluminium (Al) is 13, it means that it has 13 protons and 13 electrons., but if it lost one electron, it will have 12 electrons and 13 protons and become aluminium cation Al⁺.

Electron configuration of aluminium cation: ₁₃Al⁺ 1s² 2s² 2p⁶ 3s².

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Electron configuration of silicon cation: ₁₄Si²⁺ 1s² 2s² 2p⁶ 3s².


8 0
3 years ago
Read 2 more answers
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